Depending if you want your % to be in volume and you have 100 mL then add 212.5mL to the HCl. If you want it by mass and you have 100g of HCl then add 212.5 g of water which is about 212.5 mL anyways. #swag
To prepare 0.5N HCl from 37% HCl solution, you can use the formula C1V1 = C2V2 where C1 is the initial concentration, V1 is the initial volume, C2 is the desired concentration (0.5N), and V2 is the final volume. Calculate the volume of 37% HCl needed and dilute it to the desired volume with water.
To prepare a hydrochloric acid (HCl) solution, you can dilute concentrated hydrochloric acid with water. Always add the acid to water slowly while stirring, never add water to acid, as it can cause splattering. Be sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl.
I'm not sure about the 37 thing but here is from NIOSH method in how to prepare 6N HCL -pipette 25.64 mL of 11.7 N (37% HCL fuming) to 50 mL volumetric flask and top up with distilled water GOOD LUCK Always add acid to water.
37% HCl = { [ 37 (gHCl) / 100 (g sol'n) ] / 36.46 (gHCl/molHCl) } * 1,18 (g sol'n/mL sol'n) * 1000 (mL/L) = about 12 M HClTo prepare V Litres of 10M sol'n you should dilute [10*V]/12 Litre of 37% HCl solution to the total volume of V. Be very carefull with this addition of water.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
To prepare 0.5N HCl from 37% HCl solution, you can use the formula C1V1 = C2V2 where C1 is the initial concentration, V1 is the initial volume, C2 is the desired concentration (0.5N), and V2 is the final volume. Calculate the volume of 37% HCl needed and dilute it to the desired volume with water.
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To prepare a hydrochloric acid (HCl) solution, you can dilute concentrated hydrochloric acid with water. Always add the acid to water slowly while stirring, never add water to acid, as it can cause splattering. Be sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl.
I'm not sure about the 37 thing but here is from NIOSH method in how to prepare 6N HCL -pipette 25.64 mL of 11.7 N (37% HCL fuming) to 50 mL volumetric flask and top up with distilled water GOOD LUCK Always add acid to water.
To prepare 500ml of 0.12N HCl solution, you will need to dilute a concentrated hydrochloric acid solution. To do this, measure out 2.5ml of concentrated HCl (37% w/w) and dilute it to 500ml with distilled water. Be sure to wear appropriate safety equipment and handle the acid with caution.
37% HCl = { [ 37 (gHCl) / 100 (g sol'n) ] / 36.46 (gHCl/molHCl) } * 1,18 (g sol'n/mL sol'n) * 1000 (mL/L) = about 12 M HClTo prepare V Litres of 10M sol'n you should dilute [10*V]/12 Litre of 37% HCl solution to the total volume of V. Be very carefull with this addition of water.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
To prepare 100 ml of 1N HCl, you would need to dilute 8.4 ml of concentrated hydrochloric acid (37% w/w) with distilled water to a total volume of 100 ml.
To prepare a 1.3N HCl solution, you would need to dilute concentrated hydrochloric acid (usually 37% HCl) with water in a specific ratio. Measure out 1.3 moles of HCl in a specific volume and then dilute it to the desired final volume with water. Make sure to handle concentrated HCl with caution and follow proper safety protocols.
Try a gradual measuring pipet max. 100 mL from which you'll get 83 (+/- 1) mL. More accurate then this is not easily done and besides that it's also not usefull: the given concentrated 37% is also accurate between 36% - 38%, so you'll never get an exact 1.00 N HCl.
To prepare 100ml of 0.5N HCl solution, you would need to dilute concentrated HCl (37%) with distilled water in a volumetric flask. Measure 4.2ml of concentrated HCl, add it to the volumetric flask, and then dilute with distilled water to bring the total volume to 100ml. Mix well to ensure uniform concentration.
Density of HCl = 1.186 g/mL Molar Mass HCl = 36.46g/mol We want a concentration in mol/L so we will first convert density into g/L (1.186 g/mL)(1000mL/1L) = 1186 g/L We must now know what density 37% of that is (0.37)(1186 g/L) = 438.82 g/L Now divide this density by the molar mass to cance out the g and give you mol/L (concentration) C = (438.82g/L)/(36.46g/mol) C = 12.04 M Since HCl is monoprotic, 1M = 1N. Therefore, 37% HCl is ~12N