Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
No it wont because it is non-polar and hence cannot break the hydrogen bonds in water and get dissolved
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).
The coefficient distribution F of I2 between H2O and CCl4 refers to the partitioning of I2 between the two solvents. It quantifies the relative solubility of I2 in each solvent and is determined experimentally using a partition coefficient measurement. The coefficient distribution F is calculated as the concentration of I2 in CCl4 divided by the concentration of I2 in H2O at equilibrium.
ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
No, carbon tetrachloride (CCl4) and water (H2O) do not form a homogeneous mixture because they are immiscible in each other. Carbon tetrachloride is non-polar while water is polar, making them separate into two distinct layers.
No, CCl4 (carbon tetrachloride) is more dense than H2O (water). The density of H2O is 1 g/cm3, while the density of CCl4 is 1.59 g/cm3.
No it wont because it is non-polar and hence cannot break the hydrogen bonds in water and get dissolved
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).
No. H is hydrogen. O is oxygen. I is iodine. So this formula contains only hydrogen and oxygen.
The coefficient distribution F of I2 between H2O and CCl4 refers to the partitioning of I2 between the two solvents. It quantifies the relative solubility of I2 in each solvent and is determined experimentally using a partition coefficient measurement. The coefficient distribution F is calculated as the concentration of I2 in CCl4 divided by the concentration of I2 in H2O at equilibrium.
ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
No, carbon tetrachloride (CCl4) and water (H2O) do not form a homogeneous mixture because they are immiscible in each other. Carbon tetrachloride is non-polar while water is polar, making them separate into two distinct layers.
I2(l) + H2O(l) -> OI-(aq) + 2H+(aq) + I-(aq)
A water (H2O) molecule has a bent shape due to the arrangement of the two hydrogen atoms around the oxygen atom. A carbon tetrachloride (CCl4) molecule has a tetrahedral shape with the carbon atom in the center and four chlorine atoms at the corners of the tetrahedron.
Iodine is denser than water, so it will sink in a beaker of water rather than float.
Yes. Water melts at 0 ºC. Tetrachloromethane (Carbon tetrachloride) has a melting point of -22 ºC
Formula mass / Formula weight / Molecular mass / Molecular weight of H2O = (1*2) + 16 = 18g 1 mol of H2O = 18g H2O 1 mol of H2O = 6.023 * 10^23 molecules In 18g H2O there are 6.023 * 10^23 molecules. So, In 1g H2O there are (6.023 * 10^23) / 18 molecules = 3.346 * 10^22 molecules Therefore, In 7.3g H2O there are (3.346 * 10^22) * 7.3 molecules = 2.443 * 10^23 molecules Ans: 2.443 * 10^23 molecules