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Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
I2(l) + H2O(l) -> OI-(aq) + 2H+(aq) + I-(aq)
Sodium iodine chloride is a compound because it is composed of two or more different elements chemically bonded together. Water (H2O) is also a compound because it consists of hydrogen and oxygen chemically bonded together.
When potassium hydroxide reacts with iodine, it forms potassium iodide and potassium iodate. The balanced chemical equation for this reaction is 6 KOH + 3 I2 → 5 KI + KIO3 + 3 H2O.
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
No. H is hydrogen. O is oxygen. I is iodine. So this formula contains only hydrogen and oxygen.
Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
beaker holds the H2o been measured by the graduated cylinder
I2(l) + H2O(l) -> OI-(aq) + 2H+(aq) + I-(aq)
Lugol's Iodine = 20g Potassium Iodide + 10g Iodine dissolved in 1L H2O Gram's Iodine = 6.7g potassium iodide + 3.3g Iodine dissolved in 1L H2O Recipe's taken from Flinn Scientific Catalog I have on campus. Looks to me as Gram's is just a dilute version of Lugol's. Same ratio of KI:I just less of it. Couldn't tell you much about differences in application however.
You can deduce that, if the object was in the form of of a solid "blob" it would not float on water.
Australia
Sodium iodine chloride is a compound because it is composed of two or more different elements chemically bonded together. Water (H2O) is also a compound because it consists of hydrogen and oxygen chemically bonded together.
When potassium hydroxide reacts with iodine, it forms potassium iodide and potassium iodate. The balanced chemical equation for this reaction is 6 KOH + 3 I2 → 5 KI + KIO3 + 3 H2O.
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
The molecular equation is6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2Oand the net ionic is6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
Yes. The reaction would be Ca + H2O --> Ca(OH)2 + H2. Hope that helped.