The number of molecules in a mole is Avogadros number, 6.023 X 1023
there are 5 atoms in each molecular formula unit so we then get
6.023x1023 x 5 =3.115 X 1024 atoms.
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
Well, honey, it's simple math. The balanced chemical equation tells us that 4 moles of Al2O3 are produced for every 3 moles of Fe. So if you start with 0.60 mol of Fe, you just set up a simple ratio and find that you'll produce 0.80 mol of Al2O3. Easy peasy lemon squeezy!
There are approximately 6.022 x 10^23 atoms in 1 mol of chlorine, according to Avogadro's number.
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
There are 1 mol of oxygen atoms in 1 mol of CO2. Therefore, in 0.5 mol of CO2, there are 0.5 mol of oxygen atoms. Number of molecules = 0.5*6.022 *10^23 ≈ 3.011 *10^23 molecules
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
Well, honey, it's simple math. The balanced chemical equation tells us that 4 moles of Al2O3 are produced for every 3 moles of Fe. So if you start with 0.60 mol of Fe, you just set up a simple ratio and find that you'll produce 0.80 mol of Al2O3. Easy peasy lemon squeezy!
1 mol Cu Atoms (6.02x10^23 atoms)
There are approximately 6.022 x 10^23 atoms in 1 mol of chlorine, according to Avogadro's number.
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
There are 1 mol of oxygen atoms in 1 mol of CO2. Therefore, in 0.5 mol of CO2, there are 0.5 mol of oxygen atoms. Number of molecules = 0.5*6.022 *10^23 ≈ 3.011 *10^23 molecules
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
To find how many grams of aluminum are in 25.0g of aluminum oxide, first, determine the molar mass of aluminum oxide (Al2O3), which is 101.96 g/mol. Next, calculate the molar mass of aluminum (Al), which is 26.98 g/mol. Then, set up a ratio using the molar masses to find the amount of aluminum in 25.0g of aluminum oxide: (2 mol Al / 1 mol Al2O3) x (26.98 g Al / 101.96 g Al2O3) x 25.0g Al2O3 = 6.63g of aluminum.
In NaCl, the ratio of sodium to chloride atoms is 1:1. Therefore, in 2.35 mol of NaCl, there are 2.35 mol of sodium atoms. To find the number of sodium atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23).
2.65g(1 mol/6.022*1022atoms)
To calculate the number of grams of Al in 371 g of Al2O3, you first need to determine the molar mass of Al2O3 (102 g/mol). Then, calculate the molar mass of Al (27 g/mol). From the chemical formula Al2O3, you can see that there are 2 moles of Al for every 1 mole of Al2O3. Therefore, by using these ratios, you can determine that there are 162 g of Al in 371 g of Al2O3.