The number of molecules in a mole is Avogadros number, 6.023 X 1023
there are 5 atoms in each molecular formula unit so we then get
6.023x1023 x 5 =3.115 X 1024 atoms.
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
1 mol of He contains apx 6.02214x10^23 atoms
15.8 mol B = 9.51 X 1024 atoms.15.8 mol (6.02 X 1023/ 1 mol) = 9.5116 X 1024
175 g Ca (1 mol / 40.078 g) (6.022x10^23 atoms / 1 mol) = 2.63x10^24 Ca atoms There are 2.63x10^24 c.alcium atoms in 175 grams of calcium.
1.6 g C x 1 mol C/12 g x 6.02x10^23 atoms/mol = 8.1x10^22 atoms
1 mol Cu Atoms (6.02x10^23 atoms)
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
1 mol of He contains apx 6.02214x10^23 atoms
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
15.8 mol B = 9.51 X 1024 atoms.15.8 mol (6.02 X 1023/ 1 mol) = 9.5116 X 1024
175 g Ca (1 mol / 40.078 g) (6.022x10^23 atoms / 1 mol) = 2.63x10^24 Ca atoms There are 2.63x10^24 c.alcium atoms in 175 grams of calcium.
1.6 g C x 1 mol C/12 g x 6.02x10^23 atoms/mol = 8.1x10^22 atoms
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
2.65g(1 mol/6.022*1022atoms)
1
Exactly the same number of mols. 1 mol of oxigen atoms produces 1 mol of water molecules.
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g