2.2mol F2 x Avogadro's constant (6,022x10^23) = 1,325x10^24 atoms of F2, and x2 = 2,65x10^24 atoms of fluorine.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
There are approximately 6.023 x 10^23 atoms in 1 mole of any element, including argon. The molar mass of argon is approximately 40 grams/mol, so 22 grams of argon would contain about (6.023 x 10^23 atoms/mol) * (22 grams / 40 grams/mol) = 3.34 x 10^23 atoms of argon.
There are about 2.56 x 10^22 atoms in 10 grams of gold. This calculation is based on the atomic mass of gold (197 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol).
To find the mass of 3.40x10^22 helium atoms, you need to know the molar mass of helium, which is 4.0026 g/mol. So, the mass of 3.40x10^22 helium atoms would be 3.40x10^22 atoms * (4.0026 g/mol/6.022x10^23 atoms/mol) ≈ 2.27 grams.
There are approximately 1.34 x 10^22 carbon atoms in 1.6 g of carbon. This calculation is based on the molar mass of carbon (12 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol). To find the number of atoms, divide the mass of the sample by the molar mass of carbon, and then multiply by Avogadro's number.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
0.0602 mole K x 6.02x10^23 atoms/mole = 3.62x10^22 atoms
To calculate the number of iron atoms in 0.0178 mol of iron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Number of iron atoms = 0.0178 mol x 6.022 x 10^23 atoms/mol = 1.07 x 10^22 atoms.
There are approximately 6.023 x 10^23 atoms in 1 mole of any element, including argon. The molar mass of argon is approximately 40 grams/mol, so 22 grams of argon would contain about (6.023 x 10^23 atoms/mol) * (22 grams / 40 grams/mol) = 3.34 x 10^23 atoms of argon.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
There are about 2.56 x 10^22 atoms in 10 grams of gold. This calculation is based on the atomic mass of gold (197 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol).
To find the mass of 3.40x10^22 helium atoms, you need to know the molar mass of helium, which is 4.0026 g/mol. So, the mass of 3.40x10^22 helium atoms would be 3.40x10^22 atoms * (4.0026 g/mol/6.022x10^23 atoms/mol) ≈ 2.27 grams.
There are approximately 1.34 x 10^22 carbon atoms in 1.6 g of carbon. This calculation is based on the molar mass of carbon (12 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol). To find the number of atoms, divide the mass of the sample by the molar mass of carbon, and then multiply by Avogadro's number.
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
To find the number of atoms of He gas in 0.268 g, first calculate the moles of He using the molar mass of He (4.0026 g/mol). 0.268 g / 4.0026 g/mol ≈ 0.067 mol of He. Then, use Avogadro's number (6.022 x 10^23) to find the number of atoms: 0.067 mol x 6.022 x 10^23 atoms/mol ≈ 4.03 x 10^22 atoms of He gas in 0.268 g.
There are 9.06 x 10^22 atoms of nitrogen in 0.755 mol of N2. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of N2 (.755 mol) and the number of nitrogen atoms in one molecule of N2 (2 atoms).
0.251 moles neon (6.022 X 1023/1 mole Ne) = 1.51 X 1023 atoms of neon -------------------------------------