The number of atoms of nitrogen of 0,755 mol of N2 is 4,546716347035.10e23.
To calculate the number of atoms in 6980 grams of nitrogen, you would first convert the mass of nitrogen to moles using the molar mass of nitrogen (~14 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Overall, the calculation would be 6980 grams of nitrogen * (1 mol / 14 grams) * (6.022 x 10^23 atoms / 1 mol).
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.
To calculate the number of atoms in 6980 grams of nitrogen, you would first convert the mass of nitrogen to moles using the molar mass of nitrogen (~14 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Overall, the calculation would be 6980 grams of nitrogen * (1 mol / 14 grams) * (6.022 x 10^23 atoms / 1 mol).
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
? atoms N = 5.00g C2H5O2N x 1 mole C2H5O2N/75.08g C2H5O2N x 1 mol N/1 mol C2H5O2N x (6.022x10^23 atoms)/1 mol N = 4.01 x 10^22 atoms NTo find 75.08g:2C 2 x 12.01g = 24.02g5H 5 x 1.01g = 5.05g2O 2 x 16.00g = 32.00g1N 1 x 14.01g = 14.01gAdd the four numbers together and you get: 1 mole of C2H5O2N = 75.08 gramsYou use this as a conversion factor in the problem above.
Multiply 8.7 by avagadros number to get the number of molecules. 8.7x6.02x1023=5.24x1024 molecules of NO. as there is 1 atom of N and one of O for each molecule there are 5.24x1024 atoms of each element. this means that the total number of atoms is 2x5.24x1024 = 1.05x1025 atoms
To determine the number of atoms in 3.29 mol of Zn, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply the number of moles (3.29 mol) by Avogadro's number to find the number of atoms. The calculation would be: 3.29 mol Zn x 6.022 x 10^23 atoms/mol = 1.98 x 10^24 atoms of Zn.
To calculate the number of atoms in 80 grams of lead, you first need to determine the number of moles of lead using its molar mass (207.2 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms. So, for lead, there are approximately 3.86 x 10^23 atoms in 80 grams.
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.