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How many moles of no2 will be obtained starting with 0.4 moles of nitric acid?
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
How many moles of NO2 will be obtained strating with 0.4 moles of nitric acid?
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
How many grams would be in four 4 moles of nitric acid HNO3?
Use the Equation Moles = mass(g) / Mr (Relative molecular mass). Algebraically rearrange mass(g) = Moles X Mr We have 4 moles Mr(HNO3) is From the atomic masses in the Periodi Table 1 x H = 1 x 1 = 1 1 x N = 1 x 14 = 14 3 x O = 3 x 16 = 48 1 + 14 + 48 = 63 Substitute in mass(g) = 4 x 63 mass(HNO3) = 252 grams. NB Bearing in mind that nitric acid is usually dissolved in water , the mass of 4 moles will be greater than 252 grams, in order to account for the mass of solvent(water).
How many grams are in 1 mole of nitric acid?
The molar mass of nitric acid (HNO3) is approximately 63 grams per mole.
How many moles of calcium hydroxide are needed to react with 5.88 mL of nitric acid?
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
How many moles of no2 will be obtained starting with 0.4 moles of nitric acid?
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
How many moles of NO2 will be obtained strating with 0.4 moles of nitric acid?
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
How many grams would be in four 4 moles of nitric acid HNO3?
Use the Equation Moles = mass(g) / Mr (Relative molecular mass). Algebraically rearrange mass(g) = Moles X Mr We have 4 moles Mr(HNO3) is From the atomic masses in the Periodi Table 1 x H = 1 x 1 = 1 1 x N = 1 x 14 = 14 3 x O = 3 x 16 = 48 1 + 14 + 48 = 63 Substitute in mass(g) = 4 x 63 mass(HNO3) = 252 grams. NB Bearing in mind that nitric acid is usually dissolved in water , the mass of 4 moles will be greater than 252 grams, in order to account for the mass of solvent(water).
How many grams are in 1 mole of nitric acid?
The molar mass of nitric acid (HNO3) is approximately 63 grams per mole.
How many moles of calcium hydroxide are needed to react with 5.88 mL of nitric acid?
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M nitric acid solution?
To neutralize the nitric acid, you need a 1:1 mole ratio of sodium hydroxide to nitric acid. First, calculate the moles of nitric acid in the solution using the formula Molarity = moles/volume. Then, use the mole ratio to find the moles of sodium hydroxide needed. Finally, convert this to grams using the molar mass of sodium hydroxide.
How many moles of magnesium nitrate are produced when magnesium reacts with 8 moles of nitric acid?
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
If you need 5 moles of sulphuric acid how many grams of it will you weigh?
The mass of sulfuric acid is 490,395 grams.
How many moles of formic acid is there in 25 grams of acetic acid?
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
How many moles (precise to the nearest 0.01 mol) of nitric acid are produced from 300.00 mol of nitrogen dioxide?
To determine how many moles of nitric acid (HNO₃) are produced from nitrogen dioxide (NO₂), we refer to the balanced chemical equation for the formation of nitric acid from nitrogen dioxide and oxygen: [ 4 \text{NO}_2 + \text{O}_2 \rightarrow 4 \text{HNO}_3 ] From the equation, 4 moles of NO₂ produce 4 moles of HNO₃, indicating a 1:1 mole ratio. Therefore, from 300.00 moles of NO₂, 300.00 moles of HNO₃ will be produced.
