18 grams of water is 1 mole water.
Water is H2O.
That means there's 2 moles H and 1 Mole O.
We're looking for "O", and there's one 1.
So find the molar mass of O. (which is approx. 16)
so 16 * 1 = 16.
There are 7.24 x 10^23 atoms of oxygen in 13 grams of water. This calculation is based on the molar mass of water (18.015 g/mol) and the fact that each water molecule contains two hydrogen atoms and one oxygen atom.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
100 g water dissolve 45,8 g potassium chloride at 50 o 0C.
There are 0.47 grams of oxygen in 0.53 grams of NaHCO3.
1 mole of water is equal to 18.02 grams. H = 2 * 1.01 g = 2.02 g O = 1 * 16.00 g = 16.00 g Total = 18.02 g 1.8 g H2O * (1 mol H2O/18.02 g H2O) = 0.099889 mol H2O There are about 9.99*10-2 moles in 1.8 grams of water.
To find the number of molecules in 18 grams of water (H₂O), we first determine the number of moles. The molar mass of water is approximately 18 g/mol. Therefore, 18 grams of water corresponds to 1 mole. Since one mole contains Avogadro's number of molecules, which is about (6.022 \times 10^{23}), there are approximately (6.022 \times 10^{23}) molecules in 18 grams of water.
7
HCN is hydrocyanic acid and contains no oxygen, so producing it doesn't require oxygen. So zero grams.
To find the mass of 7 moles of water (H₂O), first note that the molar mass of water is approximately 18 grams per mole. Therefore, the mass of 7 moles of water can be calculated by multiplying the number of moles by the molar mass: 7 moles × 18 g/mol = 126 grams. Thus, the mass of 7 moles of H₂O is 126 grams.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
One McDonald's Filet-O-Fish has 400 calories and 18 grams of fat in it.
In the reaction of Fe with H₂O to produce FeO and H₂, the ratio is 3 moles of H₂O for every 1 mole of Fe. Since the molar mass of Fe is 56 g/mol and that of H₂O is 18 g/mol, we use these values to find that 750 grams of Fe will produce 750 * (3 * 18 / 56) = 857.14 grams of H₂O.
To determine the grams of glucose formed, we can use the balanced equation for photosynthesis: 6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂. From the equation, 6 grams of carbon dioxide and 6 grams of water produce 1 gram of glucose and 6 grams of oxygen. Given that 16 grams of oxygen are produced, that corresponds to 16 grams of O₂, which comes from 6 grams of CO₂ and 6 grams of H₂O multiple times. Thus, when 22 grams of CO₂ and 9 grams of H₂O are used, we can find that glucose produced is 6.67 grams.
As the molar mass of water is 18 g/mol (1*2 H + 16 O) 10 moles*18 g/mole=180 grams.
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
1 oz = 28.34 grams 1 gram = 0.03 oz