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Q=MC (t1-t2). where Q is the heat energy(5000). M is the mass of water being used (g used(0.1 kg). C is the specific heat. (4200). t1-t2 is the temperature rise occurring.

here on calculation you'll get the temp rise as 11.90 degree celcius

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How much heat is absorbed by 1.0 g of iron when its heated to 15 degrees celsius?

The specific heat capacity of iron is 0.449 J/g°C. To calculate the heat absorbed, use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass in grams, c is the specific heat capacity, and ΔT is the temperature change. Plugging in the values, the heat absorbed by 1.0 g of iron heated to 15°C is 6.735 J.


How much heat is absorbed by 60.0 grams of copper when it is heated from 293 Kelvin to 353 kelvin?

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Related Questions

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The specific heat of gold is 0.031 caloriesgram and degC. If 10.0 grams of gold were heated and the temperature of the sample changed by 20.0 and degC how many calories of heat energy were absorbed by?

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How much heat is absorbed by 1.0 g of iron when its heated to 15 degrees celsius?

The specific heat capacity of iron is 0.449 J/g°C. To calculate the heat absorbed, use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass in grams, c is the specific heat capacity, and ΔT is the temperature change. Plugging in the values, the heat absorbed by 1.0 g of iron heated to 15°C is 6.735 J.


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