It depends on the substance you are measuring and is specific to that substance. More information is needed
28g / 55.847g/mol = 0.50 mol
28/18 = 1.5556 (4 decimal places)
27,9 g iron is equal to 0,5 moles.
199.75
17
The answer is 1,25 moles iron(III) oxide.
28g Fe
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
The reaction is:4 Fe + 3 O2 = 2 Fe2O3The answer is 319,38 g.
17
10715600000000000000000
Same as 28g of cast-iron: 1 (One). 454g = 1lb.
The answer is 1,25 moles iron(III) oxide.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
28g Fe
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
7.2
The reaction is:4 Fe + 3 O2 = 2 Fe2O3The answer is 319,38 g.
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
5.0x10^25 * (1 mol / 6.022x10^23 atoms) = 83 moles of iron.
28,000 mg