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What is the mass of 2.25 mol of the element iron fe?
The answer is 125,65 g.
How many grams of iron oxide are produced from 8.00 mol of iron?
The balanced chemical equation for the formation of iron oxide is: 4 Fe + 3 O2 -> 2 Fe2O3. From the equation, we see that 4 moles of iron are required to produce 2 moles of iron oxide. Therefore, with 8.00 mol of iron, we can produce 4.00 mol of iron oxide. To find the mass of iron oxide produced, we multiply the moles of Fe2O3 by its molar mass, which is approximately 159.7 g/mol. This gives us 4.00 mol x 159.7 g/mol = 638.8 grams of iron oxide produced.
What is the mass in grams of 1.40 mol of iron (III) sulfate'?
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
How many moles are in 223.2 g of iron?
The number of moles is 4.
How many grams of iron are contained in 34 grams of fe2s3?
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
A small pin contains 0.0178 mol of iron how many atoms of iron are in the pin?
To calculate the number of iron atoms in 0.0178 mol of iron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Number of iron atoms = 0.0178 mol x 6.022 x 10^23 atoms/mol = 1.07 x 10^22 atoms.
What is the mass of 2.25 mol of the element iron fe?
The answer is 125,65 g.
How many grams of iron oxide are produced from 8.00 mol of iron?
The balanced chemical equation for the formation of iron oxide is: 4 Fe + 3 O2 -> 2 Fe2O3. From the equation, we see that 4 moles of iron are required to produce 2 moles of iron oxide. Therefore, with 8.00 mol of iron, we can produce 4.00 mol of iron oxide. To find the mass of iron oxide produced, we multiply the moles of Fe2O3 by its molar mass, which is approximately 159.7 g/mol. This gives us 4.00 mol x 159.7 g/mol = 638.8 grams of iron oxide produced.
How many iron atoms present in 5.0 mol of iron metal?
Five iron atoms have a mass of 1.3155 x 10-22 grams.
How many moles are I am 223.2 g iron (Fe)?
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
What is the mass in grams of 1.40 mol of iron (III) sulfate'?
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
How many times heavier is iron from aluminum?
Iron is approximately 2.7 times heavier than aluminum. This is due to the difference in their atomic weights - iron has an atomic weight of 55.85 g/mol, while aluminum has an atomic weight of 26.98 g/mol.
How many moles are in 223.2 g of iron?
The number of moles is 4.
How many grams of iron are contained in 34 grams of fe2s3?
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
How many particles in 25.9 mol Fe?
Number of particles=number of moles x avogadro constant = 25.9 x 6.02 x 1023
How many formula units of iron (II) oxide are needed to produce 3.6 mol Fe2O3?
7.2
How many moles are in 233.2 g iron (Fe)?
To find the number of moles in 233.2 g of iron (Fe), you need to divide the given mass by the molar mass of iron, which is approximately 55.85 g/mol. So, 233.2 g ÷ 55.85 g/mol ≈ 4.17 moles of iron.
