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The answer is 125,65 g.
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What is the mass of 2.38 mole of the element iron?
The molar mass of iron is 55.85 g/mol. To find the mass of 2.38 moles of iron, you would multiply the number of moles by the molar mass: 2.38 mol * 55.85 g/mol = 133.03 g. Therefore, the mass of 2.38 moles of iron is 133.03 grams.
What is the mass in grams of 1.40 mol of iron (III) sulfate'?
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
How many grams of iron are contained in 34 grams of fe2s3?
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
How many moles of C6H10S are in 225 grams?
To find the number of moles, you need to first calculate the molar mass of C6H10S: Carbon has a molar mass of 12.01 g/mol, hydrogen has a molar mass of 1.01 g/mol, and sulfur has a molar mass of 32.07 g/mol. Adding these up gives a molar mass of 114.17 g/mol for C6H10S. Then, divide the given mass by the molar mass to find the number of moles: 225 g / 114.17 g/mol ≈ 1.97 moles.
What is the mass of 0.806 mol of the element potassium (K) Answer in units of g.?
0,806 mol of the element potassium (K) is equal to 31,51 g.
What is the mass of 2.38 mole of the element iron?
The molar mass of iron is 55.85 g/mol. To find the mass of 2.38 moles of iron, you would multiply the number of moles by the molar mass: 2.38 mol * 55.85 g/mol = 133.03 g. Therefore, the mass of 2.38 moles of iron is 133.03 grams.
What is Iron FE's mass number?
The mass of iron depends on how much is present.
What is the mass in grams of 1.40 mol of iron (III) sulfate'?
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
What is the percent composition of a compound that contains 17.6 g of iron and 10.3 g of sulfur has a total mass of 27.9 g compound?
The percent by mass of iron in the stated compound is 100(17.6/27.9) or 63.1 %, to the justified number of significant digits. Since the compound contains only two elements, the percent by mass of sulfur is 100 - 63.1 or 36.9 %. To find the atomic percentages rather than the mass percentages, the mass for each element must be divided by the gram atomic mass of that element. 17.6 grams constitutes 17.6/55.457 or about 0.313 gram atoms of iron, and 10.3 grams of sulfur constitutes 10.3/32.06 or about 0.321 gram atoms of sulfur. The atomic ratios of the two elements in simple binary compounds such as iron sulfide must have ratios of small whole numbers. The specified compound contains about equal numbers of iron and sulfur and therefore has the formula FeS.
How many grams of iron are contained in 34 grams of fe2s3?
To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol. Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
What is the mass of 0.806 mol of the element potassium (K) Answer in units of g.?
0,806 mol of the element potassium (K) is equal to 31,51 g.
How many moles of C6H10S are in 225 grams?
To find the number of moles, you need to first calculate the molar mass of C6H10S: Carbon has a molar mass of 12.01 g/mol, hydrogen has a molar mass of 1.01 g/mol, and sulfur has a molar mass of 32.07 g/mol. Adding these up gives a molar mass of 114.17 g/mol for C6H10S. Then, divide the given mass by the molar mass to find the number of moles: 225 g / 114.17 g/mol ≈ 1.97 moles.
What is the mass of 4 moles of iron?
The molar mass of iron is approximately 55.85 g/mol. Thus, the mass of 4 moles of iron would be 4 moles * 55.85 g/mol = 223.4 grams.
What is the mass of 1.6 mol of the element?
To find the mass of 1.6 moles of an element, you need to know the molar mass of that element (found on the periodic table). Multiply the molar mass by the number of moles (1.6) to get the mass in grams. Thus, by multiplying the molar mass by 1.6 mol, you can find the mass of 1.6 moles of the element.
What is the mass of 0.75 mole of iron?
The molar mass of iron is approximately 55.85 g/mol. Therefore, the mass of 0.75 moles of iron would be 0.75 x 55.85 g/mol = 41.88 grams.
What is the mass of 3.7 mol of the element carbon c?
The molar mass of carbon is approximately 12.01 g/mol. Therefore, the mass of 3.7 mol of carbon would be 3.7 mol * 12.01 g/mol = 44.37 g.
What mass of iron is contained in 86.6 grams of CuFeS2?
To find the mass of iron in CuFeS2, we first calculate the molar mass of CuFeS2: Cu (copper) has a molar mass of 63.5 g/mol, Fe (iron) has a molar mass of 55.8 g/mol, and S (sulfur) has a molar mass of 32 g/mol. Adding these together gives a molar mass of 151.3 g/mol for CuFeS2. Next, calculate the mass percentage of iron in CuFeS2 by dividing the molar mass of iron by the molar mass of CuFeS2 and multiplying by 100. The percentage of iron is approximately 37%, so in 86.6 grams of CuFeS2, the mass of iron would be 0.37 * 86.6 grams = 32 grams.
