3.4 X 10^24 Pb atoms (1 mole Pb/6.022 X 10^23)
= 5.6 moles of lead
1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms
To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.
The molar mass of nitrogen triiodide is 394,719 g.So 88 moles is equivalent to 34 735,272 g.This strange compound has the curious property to explode when it is irradiated with alpha particles.
The equation is straight forward. One mole will react with one mole. So how many moles are in 34ml of .113M BaCl2? 0.113 / 1000, x 34 is 0.003842 moles BaCl2. So we now need to find out how many ml of Na2SO4 is 0.003842 moles. dividing 0.218 by 1000 tells you the amount of moles in 1 ml. i.e. 0.000218 moles. 0.003842/0.000218 = 17.624 ml needed to react.
The name of C14H34 is tetradecane. It is a straight-chain alkane with 14 carbon atoms and 34 hydrogen atoms in its molecular formula.
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
17.32 moles H2O (2 moles H/1 mole H2O) = 34.64 moles hydrogen
1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms
There are 34 atoms in C16H12O6: 16 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
34 moles of NaCl is equivalent to 1 986,95 g.
There are approx 2.05*1025 molecules.
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.
a KB is 1024 bytes 32KB = 32*1024 = 32,768 bytes
The molar mass of nitrogen triiodide is 394,719 g.So 88 moles is equivalent to 34 735,272 g.This strange compound has the curious property to explode when it is irradiated with alpha particles.
A butane molecule has four carbon atoms (at six protons each) and ten hydrogen atoms (at one proton each). It will make a total of 34 protons per molecule.