Assuming that the questioner meant "SO2" instead of the nonexistent "So2":
The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490 mole SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
Since oxygen is diatomic it requires 2 moles of oxygen.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490 mole SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
Since oxygen is diatomic it requires 2 moles of oxygen.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The balanced chemical equation for the reaction between carbon (C) and sulfur dioxide (SO2) is C + 2SO2 -> CS2 + 2O2. From the equation, 1 mole of C reacts with 2 moles of SO2. Therefore, you would need 0.255 moles of C to react with 0.510 moles of SO2.
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.