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How many moles of CS2 form when 3 moles of SO2 reacts?
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490mole SO2?
How many moles of C are needed to react with 0.490 mole SO2?
How many moles are in 3.82 g of SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
How many moles of oxygen are required if 4 moles of so2 are oxidized to so3?
Since oxygen is diatomic it requires 2 moles of oxygen.
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
How many moles of CS2 form when 3 moles of SO2 reacts?
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490mole SO2?
How many moles of C are needed to react with 0.490 mole SO2?
How many moles are in 3.82 g of SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
How many moles of sulfur must be burned to give 0.567 moles of so2?
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
How many moles of oxygen are required if 4 moles of so2 are oxidized to so3?
Since oxygen is diatomic it requires 2 moles of oxygen.
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
How many moles of SO2 can be produced from 67.1 moles of O2?
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
How many gram-moles in 320 grams of SO2?
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
How many moles of sulfur trioxide are formed from 3 moles of sulfur dioxide?
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
How many moles of c are needed to react with 0.510 mole of SO2?
The balanced chemical equation for the reaction between carbon (C) and sulfur dioxide (SO2) is C + 2SO2 -> CS2 + 2O2. From the equation, 1 mole of C reacts with 2 moles of SO2. Therefore, you would need 0.255 moles of C to react with 0.510 moles of SO2.
How many moles in 37.4g of SO2?
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
