One mole = always 6.02*10+23 particles of any kind (Avogadro's number, NA )
So divide yours by this one (NA) and you'll find about 14 moles
(Done by head, haven't got a calculator at the moment, sorry)
To find the number of hydrogen atoms in 90 amu of ethane (C2H6), use the molar mass of ethane to determine the number of moles present. Next, use the molecular formula of ethane to calculate the number of hydrogen atoms in one mole, and then multiply by the number of moles present to find the total number of hydrogen atoms.
methane has one carbon atom and 4 hydrogen atom.....so one mole of methane contains one mole of carbon and 4 moles of hydroge......for simplicity...one mole of water has two moles of hydrogen and one mole of oxygen....
The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To find the number of hydrogen atoms in 90 amu of ethane (C2H6), use the molar mass of ethane to determine the number of moles present. Next, use the molecular formula of ethane to calculate the number of hydrogen atoms in one mole, and then multiply by the number of moles present to find the total number of hydrogen atoms.
The answer is 97,66 moles.
methane has one carbon atom and 4 hydrogen atom.....so one mole of methane contains one mole of carbon and 4 moles of hydroge......for simplicity...one mole of water has two moles of hydrogen and one mole of oxygen....
The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.
124 grams of ethane is equal to 4,124 moles.
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
0.688 moles*6.02x1023=4.14x1023 Formula units
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To find the number of molecules of ethane in 0.334 grams, you would first convert the mass to moles using the molar mass of ethane. Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in that number of moles.
The Law of Definite Proportions states that for every mole of ethane, there will be two moles of carbon. Then there is 1 mole of carbon in one half a mole of ethane.
The term molecule is not adequate for an ionic compound; correct is formula unit.60 g NaCl contain the equivalent of 1,026 formula units.
Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.