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How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
This is based on calculations too. It contains 18 hydrogen moles.
What is the number of hydrogen atoms in 90 amu of ethane?
To find the number of hydrogen atoms in 90 amu of ethane (C2H6), use the molar mass of ethane to determine the number of moles present. Next, use the molecular formula of ethane to calculate the number of hydrogen atoms in one mole, and then multiply by the number of moles present to find the total number of hydrogen atoms.
How many grams of sodium needed to produce 2.0 mole of hydrogen gas?
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
The reaction of hydrogen with nitrogen to produce ammonia is shown below. If there are 3 moles of nitrogen how many moles of hydrogen are needed to react completely with the nitrogen?
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
How much hydrogen would be required to produce 7.5 mol of water?
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
How many moles of ethane does it take to produce 293 moles of H2O?
The answer is 97,66 moles.
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
This is based on calculations too. It contains 18 hydrogen moles.
What is the number of hydrogen atoms in 90 amu of ethane?
To find the number of hydrogen atoms in 90 amu of ethane (C2H6), use the molar mass of ethane to determine the number of moles present. Next, use the molecular formula of ethane to calculate the number of hydrogen atoms in one mole, and then multiply by the number of moles present to find the total number of hydrogen atoms.
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor?
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
What is the theoretical yield of Beryllium needed to produce 36.0g of hydrogen?
Approx. 4 moles.
How many grams of sodium needed to produce 2.0 mole of hydrogen gas?
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
How many moles of water form when 4 moles of ethane react with excess oxygen?
The combustion reaction of ethane (C2H6) with oxygen produces carbon dioxide and water. The balanced equation for the combustion of ethane is: [ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} ] From the equation, 2 moles of ethane produce 6 moles of water. Therefore, 4 moles of ethane will produce ( \frac{6}{2} \times 4 = 12 ) moles of water.
The reaction of hydrogen with nitrogen to produce ammonia is shown below. If there are 3 moles of nitrogen how many moles of hydrogen are needed to react completely with the nitrogen?
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
How much hydrogen would be required to produce 7.5 mol of water?
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
