Answer: 16 g of oxygen and 2 g of hydrogen.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
Well, honey, when 6.00 grams of hydrogen get cozy with 40.00 grams of oxygen, they throw a little party and make 46.00 grams of water. It's like a chemical love story, but with more H2O and less drama. So, grab your umbrella because it's raining water!
Aside from a few of the ultra-high-molecular-weight polymers I can't imagine a single molecule that had a mole of anything in it. But since you asked... 1. Figure out how many grams a mole of the compound weighs. Easy one: a mole of water weighs 18 grams - two grams worth of hydrogen, 16 grams of oxygen. 2. Now determine the mass of the sample you have. Our sample has a mass of 990 grams - our sample is a liter of distilled water that we took 10 ml from to make the math easier. 990 grams of water is 55 moles. 3. Multiply the number of moles you have by the number of each atom in the compound. Here we have 110 moles of hydrogen atoms (or 55 moles of H2 molecules) and 55 moles of oxygen atoms (or 27.5 moles of O2 molecules).
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
The amount of water formed from a reactionof hydrogen and oxygen conforms to the chemical equation: 2H2 + O2 --> 2H2O For every two moles of hydrogen which reacts with one mole of oxygen, 2 moles of water are formed.
To calculate the amount of hydrogen peroxide (H2O2) needed to make a 1.33 molal solution in 1500 ml of water, you first need to convert the volume of water to grams. Since the density of water is 1.0 g/ml, 1500 ml of water is equal to 1500 grams. Next, calculate the moles of H2O2 needed using the molality formula (molality = moles of solute / mass of solvent in kg). Then convert the moles to grams by multiplying by the molar mass of H2O2 (34.02 g/mol).
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
Well, honey, when 6.00 grams of hydrogen get cozy with 40.00 grams of oxygen, they throw a little party and make 46.00 grams of water. It's like a chemical love story, but with more H2O and less drama. So, grab your umbrella because it's raining water!
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
200. The formula is for every 1 Oxygen atom, 2 Hydrogen atoms must be present in water. Otherwise you would produce H2O2 (you cannot make it HO because it is never found in molecules on it's own) which is bleach.
One mole of any substance contains 6.022x10 to the power of 23 molecules of that substance. A water molecule contains two hydrogen atoms so one molecule of water has 12.044x10 to 23 hydrogen atoms.
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
To make a 2 molal solution, you would need 2 moles of lithium sulfide per 1000g of water. Since you have 1600g of water, you need 2 x (1600 / 1000) = 3.2 moles of lithium sulfide. To find the grams needed, you would multiply the molar mass of lithium sulfide (45.94 + 32.06) by the number of moles needed (3.2) to get 149.12 grams.