mass = moles x Mr
mass = 12 x (1 + 35.5)
mass = 12 x 36.5
mass = 438 grams
add water The above person is a troll.... This works for any volume of start and finish Litersc * Molesc / Litersc = Litersd * Molesd / Litersd where subscript c is concentrated and subscript d is dillute. The easier way to write this is C1V1=C2V2 so if you are going from 12M and want to go to 0.3M then it would be: 12M*V1=.3M*1L V1=.3ML/12M= 0.025L = 25mL
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
To make 0.6M HCl (hydrochloric acid), you would need to dilute a more concentrated solution of hydrochloric acid with water to achieve the desired molarity. For example, to make 1 liter of 0.6M HCl from concentrated 12M HCl, you would need to mix approximately 50 mL of 12M HCl with 950 mL of water. It is essential to add the acid to water slowly while stirring to prevent splashing and ensure safety.
To make a 5mM solution of HCl, you would need to dilute concentrated HCl (usually in the range of 10-12M) with water. The exact dilution volume will depend on the concentration of the concentrated HCl solution you have. It's crucial to wear appropriate personal protective equipment and handle concentrated HCl with care due to its corrosive nature.
Hydrochloric acid (HCl) has a density of approximately 1.2 grams per cubic centimeter, which is equivalent to roughly 10 pounds per gallon.
add water The above person is a troll.... This works for any volume of start and finish Litersc * Molesc / Litersc = Litersd * Molesd / Litersd where subscript c is concentrated and subscript d is dillute. The easier way to write this is C1V1=C2V2 so if you are going from 12M and want to go to 0.3M then it would be: 12M*V1=.3M*1L V1=.3ML/12M= 0.025L = 25mL
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
438 grams.
To make 0.6M HCl (hydrochloric acid), you would need to dilute a more concentrated solution of hydrochloric acid with water to achieve the desired molarity. For example, to make 1 liter of 0.6M HCl from concentrated 12M HCl, you would need to mix approximately 50 mL of 12M HCl with 950 mL of water. It is essential to add the acid to water slowly while stirring to prevent splashing and ensure safety.
To make a 5mM solution of HCl, you would need to dilute concentrated HCl (usually in the range of 10-12M) with water. The exact dilution volume will depend on the concentration of the concentrated HCl solution you have. It's crucial to wear appropriate personal protective equipment and handle concentrated HCl with care due to its corrosive nature.
Hydrochloric acid (HCl) has a density of approximately 1.2 grams per cubic centimeter, which is equivalent to roughly 10 pounds per gallon.
Up to $12m
around £12m ;)
The weight of one liter of hydrochloric acid would depend on its concentration. For example, a 1M solution would weigh approximately 1.18 kg, while a more concentrated solution like 12M would weigh around 11.15 kg.
a dult fl weigh 12m so 100 of them would be 26lbs
Take 83.3 mL and add water up to 1000 mL (12 times as much) The above only helps in one situation... here is the way to do it for any situation Litersc * Molesc / Litersc = Litersd * Molesd / Litersd where subscript c is concentrated and subscript d is dillute. The quicker way to write it is C1V1 = C2V2 so if you are going from 12M and want to go to 1M then it would be: 12M*V1 = 1M*1L Rearrange and solve: V1 = 1ML/12M = 0.0833 L = 83.3 mL
1m = 100cm, therefore 12m = 1200cm. 12m is > 120 cm