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Take 83.3 mL and add water up to 1000 mL (12 times as much)

The above only helps in one situation... here is the way to do it for any situation

Litersc * Molesc / Litersc = Litersd * Molesd / Litersd

where subscript c is concentrated and subscript d is dillute.

The quicker way to write it is C1V1 = C2V2

so if you are going from 12M and want to go to 1M then it would be:

12M*V1 = 1M*1L

Rearrange and solve:

V1 = 1ML/12M = 0.0833 L = 83.3 mL

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