Take 83.3 mL and add water up to 1000 mL (12 times as much)
The above only helps in one situation... here is the way to do it for any situation
Litersc * Molesc / Litersc = Litersd * Molesd / Litersd
where subscript c is concentrated and subscript d is dillute.
The quicker way to write it is C1V1 = C2V2
so if you are going from 12M and want to go to 1M then it would be:
12M*V1 = 1M*1L
Rearrange and solve:
V1 = 1ML/12M = 0.0833 L = 83.3 mL
To create a two molar solution of HCl, you would need to dissolve 73.0 grams of hydrochloric acid (HCl) in enough water to make 1 liter of solution. This would give you a 2 molar (2M) solution of HCl. Be sure to wear appropriate safety gear and handle the acid with caution.
A 0.1N (Normal) HCl solution is equivalent to a 0.1M (Molar) concentration of HCl. This means that there is 0.1 moles of HCl per liter of solution. So, the percentage concentration of a 0.1N HCl solution would be 0.1%.
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
To create a two molar solution of HCl, you would need to dissolve 73.0 grams of hydrochloric acid (HCl) in enough water to make 1 liter of solution. This would give you a 2 molar (2M) solution of HCl. Be sure to wear appropriate safety gear and handle the acid with caution.
A 0.1N (Normal) HCl solution is equivalent to a 0.1M (Molar) concentration of HCl. This means that there is 0.1 moles of HCl per liter of solution. So, the percentage concentration of a 0.1N HCl solution would be 0.1%.
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
0.1 molar HCl means that there is 0.1 moles of hydrochloric acid dissolved in 1 liter of solution. It indicates the concentration of the acid in the solution, with molarity representing the number of moles of solute per liter of solution.
To prepare several different pH solutions from a 1 Molar stock solution of HCl, you can dilute the stock solution with water to achieve the desired pH. You can use a pH meter to measure and adjust the pH as needed by adding either more stock solution or more water. Make sure to handle HCl with caution as it is a strong acid.
The pH of a 0.1 molar aqueous solution of HCl would be 1. This is because HCl is a strong acid that completely dissociates in water to produce H+ ions, resulting in a high concentration of H+ ions in solution, leading to a low pH value.
I'm not certain what is meant by 38 HCl, but I suspect it must mean 38% HCl. Typically, concentrated Hydrochloric Acid is about 36-38%. 38% W/W means each 100 grams of 38% HCl contains 38 grams of dissolved hydrogen chloride gas. Generally, concentrated HCl is considered to by 12 Formal (or less correctly, 12 Molar) which is equivalent to 12 Normal. A close approximation of 0.5M would be as follows, using a Volume/Volume prep: Combine 11.5 parts water and add 0.5 parts 12 Molar HCl. For example: 115 mL of water plus 5 mL of 12 M HCl.
To prepare 600 mL of 1 M HCl solution from a 6 M stock solution, you can use the formula: M1V1 = M2V2, where M1 = concentration of stock solution, V1 = volume of stock solution needed, M2 = final concentration, and V2 = final volume. Plugging in the values: 6 M x V1 = 1 M x 600 mL. Therefore, V1 = 100 mL. Therefore, you would need to measure 100 mL of the 6 M stock solution and dilute it to 600 mL with water to make a 1 M HCl solution.
All you have to do is convert the 6.5 g HCl solution into moles, and then plug that value into the molarity formula. If you need help, here are the formulas: # mol = (mass of substance)/(molar mass) - the molar mass is just the molecular mass of the substance expressed in grams :) Molarity (M) = (# mol solute)/(# L solution) - the solute, in this case, is the HCl, and the solution is just one, based on your question Happy Calculating!!!
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).