Thio: 1 mole S2O32- = 2 equivalent
So Eq. mass = 0.5 * (molar mass)
Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
Sodium thiosulfate reacts with iodine to form sodium iodide, sodium tetrathionate, and sulfur dioxide. This reaction is often used in titrations to determine the concentration of iodine in a solution.
· In analytical chemistry, sodium thiosulphate is used for the determination of the strength of a given solution of iodine. · Sodium thiosulphate is preferred in iodometric analysis due to the fact that sodium thiosulphate is oxidized by iodine. It is also used to determine the strength of many oxidizing agents.
Starch indicator is added after sodium thiosulphate in iodometric titrations to help visualize the endpoint of the reaction. Starch reacts with any excess iodine produced at the endpoint, forming a dark blue-black color, allowing for easier detection of when all the thiosulphate has reacted.
When sodium thiosulfate is added to an iodine solution, a reaction occurs where iodine is reduced to iodide ions by thiosulfate, causing the blue color to disappear. This is due to the formation of a colorless complex between iodine and thiosulfate, resulting in a color change.
Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
Sodium thiosulfate reacts with iodine to form sodium iodide, sodium tetrathionate, and sulfur dioxide. This reaction is often used in titrations to determine the concentration of iodine in a solution.
In iodometry sodium thiosulphate is used because it is standardized by potassium dichromate and it is the best and relaible way to standardized sodium thiosulphate using iodometric titration. Infact sodium thiosulphate is also standardized by iodimetry. The difference between both of them is only of iodine. In iodometry iodine gas is liberated that will further react with sodium thiosulphate but in iodimetry standard solution of iodine is used.
Starch acts as an indicator for the endpoint of the reaction between sodium thiosulphate and potassium iodate, as it forms a blue-black complex with iodine. This color change helps identify when all the iodine has been liberated from the reaction. This method is commonly used in titrations to determine the concentration of the sodium thiosulphate solution accurately.
The reaction is a redox reaction where chlorine is reduced to chloride ions and iodide ions are oxidized to elemental iodine. Overall, it is a displacement reaction where chlorine displaces iodine from sodium iodide to form sodium chloride and elemental iodine.
· In analytical chemistry, sodium thiosulphate is used for the determination of the strength of a given solution of iodine. · Sodium thiosulphate is preferred in iodometric analysis due to the fact that sodium thiosulphate is oxidized by iodine. It is also used to determine the strength of many oxidizing agents.
The equation for the reaction of potassium bromide with aqueous iodine is: 2KBr (aq) + I2 (aq) → 2KI (aq) + Br2 (aq) This reaction demonstrates a redox reaction where bromide ions are oxidized to bromine, and iodine is reduced to iodide.
Starch indicator is added after sodium thiosulphate in iodometric titrations to help visualize the endpoint of the reaction. Starch reacts with any excess iodine produced at the endpoint, forming a dark blue-black color, allowing for easier detection of when all the thiosulphate has reacted.
The equation between potassium iodate (KIO3) and sodium thiosulfate (Na2S2O3) involves a redox reaction. In the presence of an acid, potassium iodate is reduced to iodine (I2), while sodium thiosulfate is oxidized to form sodium tetrathionate (Na2S4O6). The balanced chemical equation for this reaction is 5Na2S2O3 + 2KIO3 + 8HCl → 5Na2S4O6 + 2I2 + 2KCl + 6H2O.
When sodium thiosulfate is added to an iodine solution, a reaction occurs where iodine is reduced to iodide ions by thiosulfate, causing the blue color to disappear. This is due to the formation of a colorless complex between iodine and thiosulfate, resulting in a color change.
Aqueous chlorine will react with aqueous sodium iodide to form aqueous sodium chloride and iodine. The balanced chemical equation for this reaction is: Cl2 (aq) + 2NaI (aq) -> 2NaCl (aq) + I2 (s)
The reaction between bromine and aqueous strontium iodide is a double displacement reaction. Bromine replaces iodide in strontium iodide, forming strontium bromide and iodine. The balanced chemical equation is: Br2 + SrI2 --> SrBr2 + I2.