No, a Bronsted acid should contain at least one polar group which can donate a proton.
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Pb2+ + 2 NO3- + 2H+ + 2I- -> PbI2 (s) + 2HNO3 (aq)
Formula: PbI2
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
The Bronsted-Lowry theory is that acids and bases are defined by the way they react with each other. Liquid ammonia and acetic acid are examples.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
Pb2+ + 2 NO3- + 2H+ + 2I- -> PbI2 (s) + 2HNO3 (aq)
Formula: PbI2
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
PBI2, or lead(II) iodide, consists of one lead (Pb) atom and two iodine (I) atoms. Therefore, there are a total of three atoms in one formula unit of PBI2.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The chemical formula for it is PbI2, but to have an equation there must be another reactant or specified phase.
Formula: PbI2
PbI2
It would be: PbI2