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The molar mass of anhydrous iron(II) nitrate is 179,91 g.
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What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 3.01 x 1023 formula units of Fe2O3?
To find the mass of 3.01 x 10^23 formula units of Fe2O3, you first need to calculate the molar mass of Fe2O3. The molar mass of Fe2O3 is 159.69 g/mol. Then, you multiply the molar mass by the number of formula units given (3.01 x 10^23) to find the total mass. The mass of 3.01 x 10^23 formula units of Fe2O3 would be 4.81 x 10^25 grams.
How many moles of Fe2O3 are in 251 g of the compound?
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
How many moles of fe2o3 are in 217g of the compound?
To determine the number of moles of Fe2O3 in 217g of the compound, you first need to calculate the molar mass of Fe2O3, which is 159.69 g/mol. Then, divide the given mass (217g) by the molar mass to find the moles. Moles = 217g / 159.69 g/mol = 1.36 moles of Fe2O3.
What is percent by mass of oxygen in Fe2O3?
To answer this question we will have to know which of the many oxides of iron you are targeting.
What is the mass of oxygen in Fe2O3 when the formula mass of Fe2O3 is 160 amu?
In the formula Fe2O3, there are two iron (Fe) atoms and three oxygen (O) atoms. The molar mass of iron is approximately 56 amu, so the mass contributed by iron is 2 × 56 amu = 112 amu. Therefore, the mass of oxygen in Fe2O3 is the total formula mass (160 amu) minus the mass of iron (112 amu), which equals 48 amu. Thus, the mass of oxygen in Fe2O3 is 48 amu.
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 3.01 x 1023 formula units of Fe2O3?
To find the mass of 3.01 x 10^23 formula units of Fe2O3, you first need to calculate the molar mass of Fe2O3. The molar mass of Fe2O3 is 159.69 g/mol. Then, you multiply the molar mass by the number of formula units given (3.01 x 10^23) to find the total mass. The mass of 3.01 x 10^23 formula units of Fe2O3 would be 4.81 x 10^25 grams.
How many moles of Fe2O3 are in 251 g of the compound?
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
How many moles of fe2o3 are in 217g of the compound?
To determine the number of moles of Fe2O3 in 217g of the compound, you first need to calculate the molar mass of Fe2O3, which is 159.69 g/mol. Then, divide the given mass (217g) by the molar mass to find the moles. Moles = 217g / 159.69 g/mol = 1.36 moles of Fe2O3.
What is percent by mass of oxygen in Fe2O3?
To answer this question we will have to know which of the many oxides of iron you are targeting.
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Iron III oxide is formed when iron combines with oxygen in the air How many grams of Fe2O3 are formed when 16.7 g of Fe reacts completely with oxygen?
To determine the mass of Fe2O3 formed, you need to first find the molar mass of Fe and Fe2O3. Then, use stoichiometry to calculate the mass of Fe2O3 that can be produced from 16.7 g of Fe. The balanced equation is 4Fe + 3O2 → 2Fe2O3, which shows that 4 mol of Fe produces 2 mol of Fe2O3. By converting 16.7 g of Fe to moles, you can then use the mole ratio to find the grams of Fe2O3 formed.
How many moles of Fe2O3 is present in 150.0g of Fe2O3?
To convert grams to moles you use the molar mass of iron (55.8 grams per mole). Divide the numbers to get the number of moles: 500 g Fe / 55.8 g/mol = 8.96 mol Fe. To calculate the number of atoms, use Avogadro's Number (6.02*1023). Multiply the number of moles and Avogadro's number: 8.96 mol * (6.02*1023) = 5.39*1024 Fe atoms.
How do you calculate the Fe content in FeO and Fe2O3?
To calculate the Fe content in FeO, you need to consider that Fe accounts for about 71.85% of the FeO compound's molecular weight. For Fe2O3, each Fe atom accounts for about 69.94% of the compound's molecular weight. After determining the molecular weight of FeO and Fe2O3, you can find the Fe content by multiplying the molecular weight of Fe by the appropriate percentage.
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
What weight of FE3O4 will furnish 0.5430g of FE2O3?
To calculate the weight of Fe3O4 needed to furnish 0.5430g of Fe2O3, you need to consider the molar masses of Fe3O4 and Fe2O3. The molar mass of Fe3O4 is 231.535 g/mol, and of Fe2O3 is 159.69 g/mol. By using the molar ratios between Fe3O4 and Fe2O3, you can determine that 0.5430g of Fe2O3 would require 0.7799g of Fe3O4.
