Hey so I am Answering this for Primavera Online High School . Which side note I have straight 'A's right know so if you are having trouble with school go to Primavera Online High School Or Middle School . It helps You and you only have two class a day. Thats great any ways the answer to this question is ....
2
C2H4 + (?)O2 => 2 CO2 + 2H2O
the answer should look like!!!
C2H4 + (2)O2 => 2 CO2 +2H2O
So In the short tha answer is two and i hope this helped you :) good luck!
The balanced equation for the complete combustion of C4H10 is 2C4H10 + 13O2 → 8CO2 + 10H2O. This equation shows that butane (C4H10) reacts with oxygen to produce carbon dioxide and water.
The balanced combustion reaction for isobutane (C4H10) is: 2C4H10 + 13O2 -> 8CO2 + 10H2O.
C4H10 + 6.5O2 4CO2 + 5H2O + heat
2C4H10 + 13O2 ==> 8CO2 + 10H2O complete combustion of isobutane
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
The balanced equation for the complete combustion of C4H10 is 2C4H10 + 13O2 → 8CO2 + 10H2O. This equation shows that butane (C4H10) reacts with oxygen to produce carbon dioxide and water.
The balanced equation for the reaction of tetracarbon decahydride (C4H10) and oxygen (O2) is: C4H10 + 6.5 O2 → 4 CO2 + 5 H2O.
The balanced combustion reaction for isobutane (C4H10) is: 2C4H10 + 13O2 -> 8CO2 + 10H2O.
C4H10 + 6.5O2 4CO2 + 5H2O + heat
2c4h10o + 13o2 -----> 8co2 + 10h2o
2C4H10 + 13O2 ==> 8CO2 + 10H2O complete combustion of isobutane
2 C4H10 (g) + 13 O2 (g) -----> 8 CO2 (g) + 10 H2O (g)
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
The combustion of Butane (C4H10) with oxygen (02) produces carbon dioxide (CO2) and water (H2O). The balanced and simplified this reaction is 2 butane + 13 water = 8 carbon dioxide and 10 water.
For the combustion of butane C4H10, the balanced chemical equation is: 2C4H10 + 13O2 -> 8CO2 + 10H2O. First, calculate the moles of butane: 58.0 g / 58.12 g/mol = 1 mole. From the balanced equation, 2 moles of butane produce 8 moles of CO2, so 1 mole of butane will produce 4 moles of CO2.
Balanced equation. 2C4H10 + 13O2 -> 8CO2 +10H2O 8.13 grams C4H10 (1 mole C4H10/58.12 grams)(10 moles H2O/2 mole C4H10)(18.016 grams/1 mole H2O) = 12.6 grams water produced
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)