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Simple conversion, take the 88 moles of propane and divide by the molar mass of propane.

88g divided by 44.11g/moles = 1.995 moles, which rounds to 2.0 moles.

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โˆ™ 2010-03-29 01:29:48
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Q: The number of moles of propane C3H8 in 88 grams of propane?
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How many moles of propane gas C3H8 are contained in 11 grams of the gas at standard conditions?

0.25 mol


What is the mass of 2 moles of propane gas C3H8?

1 mole of propane weight 44 g. So two moles will weigh 88 g.


How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g


How many grams of carbon dioxide are produced when 7.5 moles of propane burn?

The complete combustion of propane occurs according to the following balanced equation: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that three moles of carbon dioxide are produced for each mole of propane burned. Therefore, burning 7.5 moles of propane will produce 22.5 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.01; therefore, 22.5 moles has a mass of 22.5 x 44.01 or 9.9 X 102 grams, to the justified number of significant digits.


How many moles of carbon dioxide are produced when 10 moles of propane are combusted?

The reaction for the complete combustion of propane is: C3H8 + 5O2 --> 3CO2 + 4H2O So for every mole of propane combusted 3 moles of carbon dioxide are formed. Therefore combusting 10 moles of propane will form 30 moles of carbon dioxide.

Related questions

How many grams of oxygen are required to complete combustion of 2.75 moles of propane?

C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================


How many moles of propane gas C3H8 are contained in 11 grams of the gas at standard conditions?

0.25 mol


How many moles of oxygen are utilized by the complete combustion of propane?

Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.


What is the percent by mass of carbon in C3H8?

The chemical name for molecular formula C3H8 is propane. Propane has a weight of 44.10 grams per mole. Carbon (C) has a weight of 12.01 grams per mole. 1 mole of propane contains 3 moles of carbon. Therefore 81.70 percent by mass of propane is C.


How many moles of hydrogen atoms does 5 moles of propane molecules contain?

Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.


How many moles of O2 are required to react with 2.5 moles of C3H8?

C3H8 + 5O2 à 3CO2 + 4H2O So 5 moles of oxygen are needed for each mole of propane. The answer is 12.5 moles.


What is the mass of 2 moles of propane gas C3H8?

1 mole of propane weight 44 g. So two moles will weigh 88 g.


What volume would be occupied by 2 moles of propane gas C3H8 at standard conditions?

The volume of propane is 48,93 L.


How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g


How many grams of carbon dioxide are produced when 7.5 moles of propane burn?

The complete combustion of propane occurs according to the following balanced equation: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that three moles of carbon dioxide are produced for each mole of propane burned. Therefore, burning 7.5 moles of propane will produce 22.5 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.01; therefore, 22.5 moles has a mass of 22.5 x 44.01 or 9.9 X 102 grams, to the justified number of significant digits.


How many moles of carbon dioxide are produced when 10 moles of propane are combusted?

The reaction for the complete combustion of propane is: C3H8 + 5O2 --> 3CO2 + 4H2O So for every mole of propane combusted 3 moles of carbon dioxide are formed. Therefore combusting 10 moles of propane will form 30 moles of carbon dioxide.


How many propane molecules are in 22.4 liters of C3H8 gas at STP?

Propane has a density of .0018794 g/cm3. in 22.4 liters, there are 22400 cm3, so there are 42.10 grams of propane. The molar mass of propane is 44.10 g/mole, so there are .955 moles. Via Avogadro's number, there are then 5.751 E23 molecules of propane present.

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