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CO(g) + H2O(g) CO2(g) + H2(g)-The reverse reaction rate will be higher than the forward reaction rate until equilibrium is reached again.

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15y ago
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15y ago

CO2(g) + H2(g) CO(g) + H2O(g)-CO and H2O will form as CO2 and H2 are consumed.

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15y ago

2H2O2(g) 2H2O(g) + O2(g)-The reverse reaction will be favored.

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15y ago

Cl2(g) + F2(g) 2ClF(g)-1.The reverse reaction rate slowly increases until it equals the forward reaction rate. 2.Cl2 is consumed.

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7y ago

The equilibrium is not maintained.

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Q: The reaction below has reached equilibrium What will be the effect of adding CO2 to this system?
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Related questions

What is the effect of adding more water to the following equilibrium reaction?

Equilibrium is pushed to the reactant side


What correctly describes any chemical reaction that has reached equilibrium?

Forward and reverse reactions continue with no effect on the concentraction of the reactants and products.


What effect does increasing the pressure have on this equilibrium?

the forwrd reaction is favored


How does adding more reactants effect equilibrium?

Le Chatelier's principle says that, when a equilibrium is disturbed by adding or removing one or more of the contents, the system will attain a new equilibrium to minimize its effect. So when reactants are added to the system, some of they will react and give products in order to gain the new equilibrium.


What is the effect of reactant concentration?

Generally, the higher the concentrations the faster the reaction. It does not push the reaction further past the equilibrium.


What is the effect of pressure and concentration on Kc and Kp values?

Kc is the equilibrium constant of a chemical reaction related to concentrations. Kp is the equilibrium constant of a chemical reaction related to pressures. Generally, in normal conditions the effect of temperature is not so important.


When a chemical reaction and it and reverse are occurring at the same time and at the same rate the reaction has achieved?

equilibrium


What effect does the removal of heat have on the equilibrium position?

The temperature of a reaction will entirely change th equilibrium position for any given reaction. If I'm right, as you increase the temperature, the equilibrium shifts closer to the endothermic reaction as there is more heat to consume. It may also, of course, change other properties of the substances involved in the reaction, but that depends on the chemicals.


Assuming that the reaction is at equilibrium what effect does the addition of a catalyst have on the equilibruim?

a catalyst lowers the activation energy for both the forward and reverse reaction. however, it does not change the potential energy of the reactants or products. it also does not affect the heat of reaction (delta h)


What is the effect of temperature on conversion value in cstr?

Temperature affects the conversion value in a CSTR in two ways: 1) it should increase the rate of conversion 2) it should shift the equilibrium of the reaction note that in shifting the equilibrium, it shifts the equilibrium of ALL reactions including side reactions which can be suppressed or promoted If the reaction is nearing equilibrium prior to exiting the reactor, the second effect can be very significant. Increasing the rate of conversion could allow faster throughput in the reactor with the same conversion - unless the effect on equilibrium shift is significant


Does carbon Dioxide effect the production of sugars?

Yes it does, based upon the principle called Equilibrium. As being a reagent in a chemical (and/or biochemical) reaction [anabolic or catabolic makes no difference], CO2's concentration will always produce an effect on the at-equilibrium concentrations of the products of the reaction, in this case sugars.


How does increasing temperature effect endothermic reaction?

You can use LeChatelier's Principle to solve this problem. For an endothermic reaction A+heat<-->B Thus, by increasing the heat, you are shifting the equilibrium towards the reactants. The reaction will adjust itself by shifting the equilibrium to the right (producing more of the product).