0 in the elemental form, +2 or +4 in its compounds
The oxidation number of Pb in PbH4 is +2. This is because the oxidation number of hydrogen is +1, and since the sum of the oxidation numbers in a neutral compound is zero, the oxidation number of Pb must be +2 to balance the charges.
The oxidation number for Pb in PbO2 is +4. Oxygen in compounds is typically -2, so with two oxygens, the total oxidation number contributed by oxygen is -4. This means that the oxidation number of Pb must be +4 to balance the charges.
Pb3O4 contains oxygen in the 2- oxidation state. and lead in the 2+ and 4+ oxidation states.
The oxidation number of Pb in PbSO4 is +2. This is because the oxidation number of oxygen is typically -2, and the overall charge of the sulfate ion (SO4) is -2, so the oxidation number of Pb must be +2 to balance the charges in the compound.
The oxidation number of lead (Pb) in the compound PbCl2 is +2. This is because the oxidation number of chloride (Cl) is -1, and the overall charge of PbCl2 is 0, so the oxidation number of lead must be +2 to balance the charges.
The oxidation number of Pb in PbH4 is +2. This is because the oxidation number of hydrogen is +1, and since the sum of the oxidation numbers in a neutral compound is zero, the oxidation number of Pb must be +2 to balance the charges.
The oxidation number for Pb in PbO2 is +4. Oxygen in compounds is typically -2, so with two oxygens, the total oxidation number contributed by oxygen is -4. This means that the oxidation number of Pb must be +4 to balance the charges.
Pb3O4 contains oxygen in the 2- oxidation state. and lead in the 2+ and 4+ oxidation states.
The oxidation number of Pb in PbSO4 is +2. This is because the oxidation number of oxygen is typically -2, and the overall charge of the sulfate ion (SO4) is -2, so the oxidation number of Pb must be +2 to balance the charges in the compound.
The oxidation number of lead (Pb) in the compound PbCl2 is +2. This is because the oxidation number of chloride (Cl) is -1, and the overall charge of PbCl2 is 0, so the oxidation number of lead must be +2 to balance the charges.
O is 2- and there are two of them so Pb would have to be 4+
The oxidation number of lead (Pb) in the compound PbCl2 has to be what?
The oxidation number of lead (Pb) in PbF4 is +4. Fluorine (F) always has an oxidation number of -1, so for PbF4, the four fluorine atoms contribute a total oxidation number of -4. This means the lead atom must have an oxidation number of +4 to balance the charge.
In PbI2, lead (Pb) would have an oxidation number of +2, and iodine (I) would have an oxidation number of -1. This is because iodine typically has an oxidation number of -1 in ionic compounds, while lead usually has an oxidation number of +2.
Possible valences of plutonium are: +2,3,4,5,6.
Oxygen is in this case -2. There are three oxygens in this problem, so the total is -6. Pb's oxidation number is the same as its ionic charge, which is +2. Everything must equal zero out if you add all the numbers together. +2(Pb)+(Sulfur's oxidation number)-6(Oxygen)= 0 -4+(4)=0 Pb=-2 S=+4 O=-2
The oxidation number of lead (Pb) in lead nitrate (Pb(NO3)2) is +2. In this compound, the nitrate ion (NO3-) carries a charge of -1, and there are two nitrate ions for every lead ion. The overall compound must be electrically neutral, making the oxidation number of lead in lead nitrate +2.