an alcohol reacts with a strong base to from an alkoxide ion
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.
The reaction between C5H10Br2 and NaNH2 in liquid ammonia results in the formation of a diene compound known as 1,5-hexadiene. The NaNH2 acts as a strong base and abstracts a proton from the dihalide compound, leading to the formation of the diene product.
The reaction involving NaNH2 and NH3 is a nucleophilic substitution reaction. In this reaction, the NaNH2 acts as a strong base and replaces a hydrogen atom in NH3, forming a new compound. This reaction is commonly used in organic synthesis to introduce new functional groups into molecules.
Various substances can dissolve in alcohol, including sugars, flavorings, chemicals, medications, and minerals. This property makes alcohol a commonly used solvent for extracting and preserving different compounds in fields like food, pharmaceuticals, and cosmetics.
NaNH2 is a base because it can accept a proton (H+) from an acid to form ammonia (NH3) and the conjugate base of the acid. This reaction results in the formation of NH4+ and N3- ions, showing the ability of NaNH2 to accept protons and act as a base.
Well ammonia is a weak base and and NaNH2 is a strong base, so overall, you've got a pretty strong base.
Well ammonia is a weak base and and NaNH2 is a strong base, so overall, you've got a pretty strong base.
Yes, NaNH2 (sodium amide) is highly soluble in water due to its ionic nature. When dissolved in water, it dissociates into sodium ions (Na+) and amide ions (NH2-) which are stabilized by hydration.
solvent
solvent
Sugar Is dissolved in alcohol
When iodine is dissolved in alcohol, the resulting mixture is known as tincture of iodine.
A drop of water in a jar of pure alcohol would be water dissolved in alcohol.
Yes
solvent!
Perfume can be dissolved in alcohol.
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.