Yes
Pyramids have an extraordinarily wide base and an extraordinarily narrow top - this designis very stable.
The Americans that benefited the most from the Tariff of 1816 were the manufacturers. The western and northern states, having a strong industrial base, strongly supported the tariff.
Strong enough to defeat any unit and base, if you can afford one, just send it after an orbital strike and it's done. It does ~400 per hit so the enemy base won't last long.
The Philippines was a strong base for US military power and had to be controlled by Japan if they were going to expand in east Asia without US interference.
why is a strong economy important
Well ammonia is a weak base and and NaNH2 is a strong base, so overall, you've got a pretty strong base.
Well ammonia is a weak base and and NaNH2 is a strong base, so overall, you've got a pretty strong base.
NaNH2 is a base because it can accept a proton (H+) from an acid to form ammonia (NH3) and the conjugate base of the acid. This reaction results in the formation of NH4+ and N3- ions, showing the ability of NaNH2 to accept protons and act as a base.
When NaNH2 is dissolved in an alcohol, it acts as a strong base that can deprotonate the alcohol molecule on its α-carbon, forming an alkoxide ion. This alkoxide ion can undergo further reactions like nucleophilic substitution or elimination reactions.
The reaction between C5H10Br2 and NaNH2 in liquid ammonia results in the formation of a diene compound known as 1,5-hexadiene. The NaNH2 acts as a strong base and abstracts a proton from the dihalide compound, leading to the formation of the diene product.
The reaction involving NaNH2 and NH3 is a nucleophilic substitution reaction. In this reaction, the NaNH2 acts as a strong base and replaces a hydrogen atom in NH3, forming a new compound. This reaction is commonly used in organic synthesis to introduce new functional groups into molecules.
When pyridine reacts with sodamide, the products obtained are sodamide anion (NaNH2) and a protonated pyridine molecule. The NaNH2 acts as a strong base and abstracts a proton from the pyridine molecule to form sodamide anion and a protonated pyridine.
A terminal alkyne with a proton missing; reacts as strong base and nucleophile RC(triplebond)C(-) The C- has a lone pair and a formal negative charge You can make one by reacting a terminal alkyne with a strong base such as NaNH2
The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.
It is a strong base.
It is a strong base.
No, CH3O is not a strong base. It is a weak base.