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If NaNH2 is dissolved in liquid ammonia it is an acid or a base?

Well ammonia is a weak base and and NaNH2 is a strong base, so overall, you've got a pretty strong base.


If NaNH2 is dissolved in liquid ammonia is it an acid or a base?

Well ammonia is a weak base and and NaNH2 is a strong base, so overall, you've got a pretty strong base.


WHY is NaNH2 a base?

NaNH2 is a base because it can accept a proton (H+) from an acid to form ammonia (NH3) and the conjugate base of the acid. This reaction results in the formation of NH4+ and N3- ions, showing the ability of NaNH2 to accept protons and act as a base.


What do you get when NaNH2 is dissolved in an alcohol?

When NaNH2 is dissolved in an alcohol, it acts as a strong base that can deprotonate the alcohol molecule on its α-carbon, forming an alkoxide ion. This alkoxide ion can undergo further reactions like nucleophilic substitution or elimination reactions.


What is the product when C5H10Br2 reacts with NaNH2 in liquid ammonia?

The reaction between C5H10Br2 and NaNH2 in liquid ammonia results in the formation of a diene compound known as 1,5-hexadiene. The NaNH2 acts as a strong base and abstracts a proton from the dihalide compound, leading to the formation of the diene product.


What is the mechanism of the reaction involving nanh2 and nh3?

The reaction involving NaNH2 and NH3 is a nucleophilic substitution reaction. In this reaction, the NaNH2 acts as a strong base and replaces a hydrogen atom in NH3, forming a new compound. This reaction is commonly used in organic synthesis to introduce new functional groups into molecules.


What is the products obtained when pyridine reacts with sodamide?

When pyridine reacts with sodamide, the products obtained are sodamide anion (NaNH2) and a protonated pyridine molecule. The NaNH2 acts as a strong base and abstracts a proton from the pyridine molecule to form sodamide anion and a protonated pyridine.


What is an acetylide ion?

A terminal alkyne with a proton missing; reacts as strong base and nucleophile RC(triplebond)C(-) The C- has a lone pair and a formal negative charge You can make one by reacting a terminal alkyne with a strong base such as NaNH2


How does the reaction between NaNH2 and CH3I proceed?

The reaction between NaNH2 and CH3I proceeds through a nucleophilic substitution reaction, where the NaNH2 acts as a nucleophile attacking the carbon atom in CH3I, leading to the formation of a new compound and the release of sodium iodide as a byproduct.


Is milk a weak base or strong base?

It is a strong base.


Is milk a strong base or weak base?

It is a strong base.


Is ch3o a strong base?

No, CH3O is not a strong base. It is a weak base.