The reaction is endothermic.
This is an endothermic chemical reaction.
The reaction is exothermic.
When H is positive and S is negative
If the ∆H is positive and the ∆S is positive, then the reaction is entropy driven. If the ∆H is negative and the ∆S is negative, then the reaction is enthalpy driven. If ∆H is positive and ∆S is negative, then the reaction is driven by neither of these. If ∆H is negative and ∆S is positive, then the reaction is driven by both of these.
∆G = ∆H - T∆S and ∆G has to be negative for the reaction to be spontaneous. So, ultimately the effect of temperature will depend on the value of ∆H. If ∆H is negative, and ∆S is positive, then temperature won't matter, and reaction will be spontaneous. If ∆H is positive, and ∆S is positive, then a high temperature will favor spontaneity. If ∆H is negative and ∆S is negative, then a low temperature will favor spontaneity. So, the answer to your question is the higher the temperature the more likely the reaction will occur spontaneously.
This is an endothermic chemical reaction.
When H and S are both positive
The reaction is exothermic.
The reaction is exothermic.
When H is positive and S is negative
the reaction is endothermic
yes
If the ∆H is positive and the ∆S is positive, then the reaction is entropy driven. If the ∆H is negative and the ∆S is negative, then the reaction is enthalpy driven. If ∆H is positive and ∆S is negative, then the reaction is driven by neither of these. If ∆H is negative and ∆S is positive, then the reaction is driven by both of these.
∆G = ∆H - T∆S and ∆G has to be negative for the reaction to be spontaneous. So, ultimately the effect of temperature will depend on the value of ∆H. If ∆H is negative, and ∆S is positive, then temperature won't matter, and reaction will be spontaneous. If ∆H is positive, and ∆S is positive, then a high temperature will favor spontaneity. If ∆H is negative and ∆S is negative, then a low temperature will favor spontaneity. So, the answer to your question is the higher the temperature the more likely the reaction will occur spontaneously.
when H is negative and S is positive
A high temperature will make it spontaneous.
A high temperature will make it spontaneous.