The "2" in MgBr2 indicates that magnesium (Mg) forms an ionic compound with two bromide ions (Br-). This means that magnesium will have a 2+ charge to balance the 2- charge of the two bromide ions.
The ionic formula for Mg and Br is MgBr2, with magnesium having a 2+ charge and bromine having a 1- charge. MgBr2 indicates that two bromide ions combine with one magnesium ion in the compound.
Magnesium bromide has the chemical formula MgBr2. It is composed of one magnesium ion (Mg2+) and two bromide ions (Br-).
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
The chemical formula for magnesium bromide (MgBr) can be represented in Lewis dot diagram form as follows: Magnesium (Mg) with 2 dots (representing 2 valence electrons) and Bromine (Br) with 7 dots (representing 7 valence electrons) sharing one pair of electrons.
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
The chemical formula of magnesium dibromide is MgBr2.
The ionic formula for Mg and Br is MgBr2, with magnesium having a 2+ charge and bromine having a 1- charge. MgBr2 indicates that two bromide ions combine with one magnesium ion in the compound.
Formula: MgBr2
MgBr2
MgBr2.
The chemical formula for magnesium bromide is MgBr2. This compound is composed of one magnesium ion (Mg2+) and two bromide ions (Br-).
2Mg + Br2 ---> 2MgBr Magnesium Bromide
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.
The chemical formula for magnesium perbromate is Mg(BrO4)2.
Magnesium bromide has the chemical formula MgBr2. It is composed of one magnesium ion (Mg2+) and two bromide ions (Br-).
magnesium bromide
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.