1.34 moles Ca x 6.02x10^23 atoms Ca/mole Ca = 8.07x10^23 atoms of Ca
In Ca(HCO3)2, there are 2 moles of carbonate ions (CO3^2-), each containing 3 atoms. So there are 6 atoms in 1 molecule of Ca(HCO3)2. Therefore, in 4 moles of Ca(HCO3)2, there are 4 x 6 = 24 moles of atoms.
There are 0.18 moles of Ca2+ ions in 0.18 moles of CaF2.
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
In 1.5 moles of CaCl2, you would have 3 moles of ions or atoms of calcium and 3 moles of ions of chloride. Since CaCl2 dissociates into 1 calcium ion (Ca2+) and 2 chloride ions (2Cl-), this means you would have 3 moles of calcium ions and 6 moles of chloride ions in total.
In Ca(HCO3)2, there are 2 moles of carbonate ions (CO3^2-), each containing 3 atoms. So there are 6 atoms in 1 molecule of Ca(HCO3)2. Therefore, in 4 moles of Ca(HCO3)2, there are 4 x 6 = 24 moles of atoms.
3 x 6.02E23 molecules.
There are 0.18 moles of Ca2+ ions in 0.18 moles of CaF2.
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.
12.7 moles calcium (6.022 X 10^23/1 mole Ca) 7.65 X 10^24 atoms of calcium in 12.7 moles.
To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
10 moles of calcium has more atoms than 10 moles of carbon, as calcium has a higher atomic number and atomic weight compared to carbon. Each mole contains Avogadro's number of atoms, so the element with the larger atomic weight will have more atoms in 10 moles.
There are 4.84 x 10^24 atoms present in 8.00 moles of zirconium because one mole of any element contains Avogadro's number of atoms, which is 6.022 x 10^23.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
To find the number of atoms in 181 g of calcium, first calculate the number of moles of calcium using its molar mass (40.08 g/mol). This comes to 4.5 moles. Next, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, there are approximately 2.7 x 10^24 atoms in 181 g of calcium.