1.34 moles Ca x 6.02x10^23 atoms Ca/mole Ca = 8.07x10^23 atoms of Ca
44 moles of atoms
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
First calculate the moles of Calcium Moles(Ca) = 169g/ 40 (Atomic Mass) moles(Ca) = 4.225 moles. Remember the Avogdro No. which is the number of ato,ms/molecules in one mole. Hence 6.022 x 10^*23) = 1 mole. We have 4.225 moles So multiplying 4.225 X 6.022 x 10^(23) = 2.54 x 10^(24) atoms)
Answers:- 9,033.10 ex. 23 calcium atoms- 18,066.10 ex.23 chlorine atoms
44 moles of atoms
48,177 134 32.1023 atoms
Ca!
3 moles of Ca would have 1.806 × 10^24 atoms.
25.0 moles Ca x 6.02x10^23 atoms/mole = 1.50x10^25 atoms
12.7 moles calcium (6.022 X 10^23/1 mole Ca) 7.65 X 10^24 atoms of calcium in 12.7 moles.
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
The atomic mass of calcium, Ca is 40.1. First we calculate the amount in moles of calcium in a 98.5g pure sample.Amount of Ca = 98.5/40.1 = 2.46mol So there are 2.46 moles of Ca (or Ca atoms).
Ca (NO3)2 So the number of Ca atoms will just be Avogadro's constant, L
1mol Ca = 40 gCa 45.8g/40g = 1.145 mol Ca
First calculate the moles of Calcium Moles(Ca) = 169g/ 40 (Atomic Mass) moles(Ca) = 4.225 moles. Remember the Avogdro No. which is the number of ato,ms/molecules in one mole. Hence 6.022 x 10^*23) = 1 mole. We have 4.225 moles So multiplying 4.225 X 6.022 x 10^(23) = 2.54 x 10^(24) atoms)
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.