Cu & MgSO4 do NOT react. because in the Reactivity Series magnesium is MORE reactive than copper. So Mg will preferentially oxidise before Cu,
Since it is already oxidised in MgSO4 as the ion Mg^(2+), it has already reacted, by ionising two electrons.
The chemical reaction between magnesium (Mg) and copper sulfate (CuSO4) produces magnesium sulfate (MgSO4) and copper (Cu) according to the equation: Mg + CuSO4 -> MgSO4 + Cu
A displacement reaction takes place as magnesium is above copper in the electrochemical series. This reaction would produce copper (Cu) and magnesium sulphate (MgSO4) (sorry i cant find an arrow symbol for below) Mg + CuSO4 (arrow) Cu + MgSO4
Mg (s) + CuSO4 (aq) => Cu (s) + MgSO4 (aq).
The balanced equation for magnesium chloride (MgCl2) plus sulfuric acid (H2SO4) is: MgCl2 + H2SO4 → MgSO4 + 2HCl.
Cu+
The chemical reaction between magnesium (Mg) and copper sulfate (CuSO4) produces magnesium sulfate (MgSO4) and copper (Cu) according to the equation: Mg + CuSO4 -> MgSO4 + Cu
A displacement reaction takes place as magnesium is above copper in the electrochemical series. This reaction would produce copper (Cu) and magnesium sulphate (MgSO4) (sorry i cant find an arrow symbol for below) Mg + CuSO4 (arrow) Cu + MgSO4
the produc of the reaction is Mg(s) + CuSO4 (aq)--> MgSO4(aq) + Cu(S)+H2 ***NOTE**** the H2 is coming from CuSO4 in a aqueous solution, thus H2O is involved in the reaction. I believe that this would make the precipitate call Copper (II) Oxide. Thus, shouldn't the equation be..... Mg(s) + CuSO4 (aq) --(H2O)--> MgSO4 (aq) +CuO (s) + H2 (g) N.B. Hi Classmates! Galingan ninyo ang paggawa ng seatwork natin ha. Copy nalang ako sa inyo
the balanced chemical equation for copper ii sulphate magnesium powder is given as follows.Its a displacement reaction .Mg+CuSO4⟶Mg2SO4+Cu.Its a balanced chemical reaction.
Mg (s) + CuSO4 (aq) => Cu (s) + MgSO4 (aq).
In the reaction between CuSO4 and Mg, magnesium (Mg) is oxidized while copper (Cu) is reduced. Magnesium loses electrons to form Mg²⁺ ions, indicating oxidation, while copper ions (Cu²⁺) gain electrons to form elemental copper, indicating reduction. Thus, Mg is the reducing agent and Cu²⁺ is the oxidizing agent in this reaction.
The cation of MgSO4·7H2O is Mg^2+ (magnesium ion).
Cu(I), cuprous, Cu+.
mg + CuCl2 + MgCl2 + Cu Mg + Cu^+2 = Mg^+2 + Cu
Cu+
The balanced equation for magnesium chloride (MgCl2) plus sulfuric acid (H2SO4) is: MgCl2 + H2SO4 → MgSO4 + 2HCl.
The oxidation number of sulfur in MgSO4 is +6. This is because the oxidation state of magnesium is +2 and oxygen is always -2, so the algebraic sum of the oxidation states in MgSO4 must add up to zero.