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I'm assuming we are talking about Rn222.
Rn222 is part of the U238 chain (also known as the Radium series).
Rn222 (half life 3.8 days) -> Po218 + alpha particle (5.59 MeV)
Po218 (half life 3.1 minutes) -> Pb214 + alpha particle (6.115 MeV)
Pb214 (half life 26.8 minutes) -> Bi214 + beta- particle (1.024 MeV)
Bi214 (half life 19.9 minutes) -> Po214 + beta- particle (3.272 MeV)
Po214 (half life .164 ms) -> Pb210 + alpha particle (7.883 MeV)
Pb210 (half life 22.3 years) -> Bi210 + beta- particle (64 keV)
Bi210 (half life 5.013 days) -> Po210 + beta- particle (1.426 MeV)
Po210 (half life 138.4 days) -> Pb206 + alpha particle (5.407 MeV)
Pb206 (lead) is stable so that is the end of the chain.
What else can I help you with?
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
What is the nuclear equation for the alpha decay of 242 Pu?
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
What shows a balanced nuclear equation for the beta decay pf potassium-42?
The balanced nuclear equation for the beta decay of potassium-42 is: ^42K -> ^42Ca + e^- + νe
What is the nuclear equation of the decay of uranium 238?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
When uranium-238 is transformed into thorium-234 it is represented by a balanced equation What is missing from the equation of U-238 undergoing radioactive decay?
What is missing is the type of decay that occurs during the transformation. For example, uranium-238 decays into thorium-234 through alpha decay, so the missing component would be the emission of an alpha particle in the balanced equation.
What is the balanced nuclear equation for the alpha decay of thorium 230?
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
How do you write a balanced nuclear equation for the alpha decay of polonium -216?
Po-216- -----------------> Pb-212
What is the nuclear equation for the decay of radium 226?
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
What is the balanced equation for the alpha decay of radium 228?
224
What is the nuclear equation for the alpha decay of uranium 239?
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
What is the nuclear equation for the alpha decay of 242 Pu?
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
What is the nuclear decay equation for astatine 213?
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
What is the nuclear decay equation for bohrium-265?
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
What shows a balanced nuclear equation for the beta decay pf potassium-42?
The balanced nuclear equation for the beta decay of potassium-42 is: ^42K -> ^42Ca + e^- + νe
What would the balanced equation for the alpha decay of thorium 229 be?
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
What is the nuclear equation of the decay of uranium 238?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
