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What is a balanced nuclear equation for the alpha decay of Rn-22?
Wiki User
∙ 13y ago
I'm assuming we are talking about Rn222.
Rn222 is part of the U238 chain (also known as the Radium series).
Rn222 (half life 3.8 days) -> Po218 + alpha particle (5.59 MeV)
Po218 (half life 3.1 minutes) -> Pb214 + alpha particle (6.115 MeV)
Pb214 (half life 26.8 minutes) -> Bi214 + beta- particle (1.024 MeV)
Bi214 (half life 19.9 minutes) -> Po214 + beta- particle (3.272 MeV)
Po214 (half life .164 ms) -> Pb210 + alpha particle (7.883 MeV)
Pb210 (half life 22.3 years) -> Bi210 + beta- particle (64 keV)
Bi210 (half life 5.013 days) -> Po210 + beta- particle (1.426 MeV)
Po210 (half life 138.4 days) -> Pb206 + alpha particle (5.407 MeV)
Pb206 (lead) is stable so that is the end of the chain.
Wiki User
∙ 13y ago
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Write a balanced nuclear equation for the radioactive decay of a boron-10 plus a neutron results in the formation of another element and the release of an alpha particle?
lithium
What is the nuclear equation for the alpha decay of 242 Pu?
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
When uranium-238 is transformed into thorium-234 it is represented by a balanced equation What is missing from the equation of U-238 undergoing radioactive decay?
alpha
What is the nuclear equation of the decay of uranium 238?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
What is the balanced nuclear equation for the alpha decay of thorium 230?
Th-230(alpha)Ra-226.
How do you write a balanced nuclear equation for the alpha decay of polonium -216?
Po-216- -----------------> Pb-212
What is the nuclear equation for the decay of radium 226?
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
What is the balanced equation for the alpha decay of radium 228?
224
What is the nuclear equation for the alpha decay of uranium 239?
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
What is the nuclear equation for the decay of Po210 if it undergoes 2 alpha decay then a beta decay followed by another alpha decay.?
92Au 282Xe +13S
What is the nuclear decay equation for bohrium-265?
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
What is the nuclear decay equation for astatine 213?
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
What would the balanced equation for the alpha decay of thorium 229 be?
229Th-------alpha particle-----------225Ra
Write a balanced nuclear equation for the radioactive decay of a boron-10 plus a neutron results in the formation of another element and the release of an alpha particle?
lithium
What is the nuclear equation for the alpha decay of 242 Pu?
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
