If inner d orbital is involved in hybridization, it is called inner d orbital complex.
and if outer d orbital is involved in hybridization then it is called 'outer d orbital complex'.
The 5D orbital would have more energy than the 5P orbital. This is due to the fact that in general, d orbitals have higher energy than p orbitals because they experience more shielding from inner electrons and have a more complex shape which leads to higher energy.
In nitrogen, the inner shell consists of two electrons, which fill the 1s orbital.
The orbital diagram of cesium (Cs) would show its electron configuration as [Xe] 6s1, where [Xe] represents the electron configuration of the inner noble gas xenon. This means that cesium has one valence electron in its outermost 6s orbital.
Lets first take the case of the d3 compound. The no.of orbitals in the 3d shell is 5. If three electrons occupy three orbitals then there are two free orbitals.Therefore According to Valence bond theory the six water ligands will use the two inner d orbitals the outer s and the p orbitals to form an inner orbital complex with hybrisation d2sp3. In the second case we have the d5 compund. Since there are five electrons in the d subshell the five electrons singly occupy all the five d orbitals. Here 's where the concept of the weak ligand comes in. Since water is a weak ligand it cannot force pairing of the unpaired d electrons to make room for an inner orbital complex. Thus it has to use the outer d orbital to form an outer orbital complex with hybridisation of sp3d2. Since the Inner orbital (low spin) complex is more stable than the outer orbital (high spin) complex. Thus d3 configuration is more stable than d5 configuration in aqueous medium.
I would think the s orbital, because it is closer to the nucleus, and because the outer energy level holds more energy than the inner ones.
i think it the inner part of the object
Yes, dsp2 hybridized orbitals are typically associated with inner orbital complexes. In these complexes, the central metal ion's d and s orbitals mix with the p orbitals of the ligands to form hybridized orbitals. This arrangement leads to geometric shapes like square planar or tetrahedral.
No, Q is the outermost orbital. K is the first one.
The 5D orbital would have more energy than the 5P orbital. This is due to the fact that in general, d orbitals have higher energy than p orbitals because they experience more shielding from inner electrons and have a more complex shape which leads to higher energy.
Mercury is the fastest orbiting planet in the inner Solar System, with an average orbital velocity of 47.87 km/s.
There isn't any relatonship between the orbital distance of the planet, and its rotational speed.
They are farther away and have larger orbital periods.
Oxygen has 2 electrons in the innermost orbital and 6 in the outermost (valence) orbital.
In nitrogen, the inner shell consists of two electrons, which fill the 1s orbital.
The inner planets (Mercury, Venus, Earth, and Mars) have relatively low orbital inclinations compared to the outer planets (Jupiter, Saturn, Uranus, and Neptune). The inner planets orbit the Sun in a more or less flat plane known as the ecliptic, while the outer planets have more inclined orbits relative to this plane.
The orbital diagram of cesium (Cs) would show its electron configuration as [Xe] 6s1, where [Xe] represents the electron configuration of the inner noble gas xenon. This means that cesium has one valence electron in its outermost 6s orbital.
Inner planets are typically rocky, smaller in size, have shorter orbital periods, and lack rings. Outer planets are gaseous or icy, larger in size, have longer orbital periods, and possess rings and many moons. Additionally, inner planets are closer to the Sun, while outer planets are farther away.