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Cr+6 SO3-2 ------> these are the ions and their charges

Cr+6 SO3-2 SO3-2 SO3-2 ----> the charges have to add up to zero, so three +2 sulfite ions cancels out one +6 Cr ion.

Cr(SO3)3 ----> simplify

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Wiki User

15y ago
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15y ago
Cr2(So3)3
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2mo ago

The formula for chromium (VI) sulfite is Cr2(SO3)3.

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Q: What is formula for chromium VI sulfite?
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Related questions

What is the chemical formula of chromium ( vi) sulfide?

The chemical formula of chromium(VI) sulfide is Cr2S3.


What is the chemical formula for the compound formed between chromium(VI) and chlorine?

The compound formed between chromium(VI) and chlorine is chromium(VI) chloride, with the chemical formula CrCl6.


What is the formula for chromium (VI) phosphide?

Formula: CrP2


What is the chemical formula for the compound formed between chromium VI and selenium?

The chemical formula for the compound formed between chromium VI and selenium is Cr2Se3.


What is the formulae for chromium VI phosphate?

The chemical formula for chromium VI phosphate is Cr(PO4)2.


What is the formula of Cro3?

CrO3 is Chromium(VI) oxide also called Chromium trioxide


What is formula for chromium sulfide?

Chromium VI sulphate Cr(SO4)3


How do you write chromium VI sulfate as a formula?

The chemical formula for chromium VI sulfate is Cr2(SO4)3. This compound contains two chromium ions (Cr) and three sulfate ions (SO4) in a 2:3 ratio, forming a neutral compound.


What is the stock system name for CrSO3?

iron(II


What is the formula of chromium ion?

The formula of chromium ion depends on its charge. For example, chromium in the +3 oxidation state forms the chromic ion (Cr3+), while chromium in the +6 oxidation state forms the chromate ion (CrO4^2-).


What is the chemical name for this compound Cr2 parenthese SO3 parenthese 3?

The chemical name for the compound Cr2(SO3)3 is chromium(III) sulfite.


What is the formula of chromium II sulfate?

Annon:The chemical formula of chromium II sulfate is CrSO4.Miki-San-X: ActuallySince this is probably Ionic naming since it starts with a metal and ends with a non metal you would take chromium (II) Sulfate and cross them-Like so-Start:Cr(II) SO4 (-2)We know that sulfate is SO4 with a -2 superscript and that chromium is a transition metal, but that it has a positive charge to counteract the negative charge of the -2.You will drop the charge and cross them-Cr2(SO4)2since you brought the -2 from the sulfate down to the chromium it becomes positive 2 because you dropped the charge before crossing. The reason you put the (SO4) in parenthesis is because you cannot, in a problem like this, have 42 next to your polyatomic ion. You have TWO of that ion, NOT 42.Hope I helped