0.20 M CaBr2
You need to make this value in a litre. The sum is 1.5/750*100. This gives you a 2 molar solution.
CaBr2 will dissociate into Ca2+ ions and two Br- ions. In aqueous solution of CaBr2, water is the solvent and Ca2+ ions and Br- ions are the solute particles.
0,31 moles of anhydrous CaBr2 is equal to 61,966 g.
mole=moles/liters -> moles=mole*liters moles=7.65 * 4.65 = 35.5725 Molar mass= [40.007+(2)(79.904)]*1 g/mol = 199.815 g/mol 35.5725*199.815= 7107.9190875 g 7108 grams of CaBr2 are needed
All you have to do is flip the numbers and reduce. If you have Ca+2 and Br-, Switch the numbers so you get CaBr2. 1 and 2 do not have any common factors so you don't have to reduce! CaBr2 is the final answer.
You need to make this value in a litre. The sum is 1.5/750*100. This gives you a 2 molar solution.
Molality (mol/kg, molal, or m) denotes the number of moles of solute per kilogram of solvent (not solution!).So if it is supposed that 1 L water weights 1 kg (in fact it is 0.99232 kg/L at 20oC) then the molality is 0.50 mole/kg.Contrarily:[Molarity (in units of mol/L, molar, or M) or molar concentration denotes the number of moles of a given substance (solute) per liter of solution].
CaBr2 will dissociate into Ca2+ ions and two Br- ions. In aqueous solution of CaBr2, water is the solvent and Ca2+ ions and Br- ions are the solute particles.
CaBr2 :)
Not many! 5.0 grams CaBr2 (1 mole/199.88 grams CaBr2) = 0.025 moles CaBr2
0,31 moles of anhydrous CaBr2 is equal to 61,966 g.
CaBr2
The chemical formula of chlorine gas is Cl2 and the symbol of the element is Cl; whereas the formula of calcium bromide is CaBr2. I hope u got it !!!!!!!!!!
mole=moles/liters -> moles=mole*liters moles=7.65 * 4.65 = 35.5725 Molar mass= [40.007+(2)(79.904)]*1 g/mol = 199.815 g/mol 35.5725*199.815= 7107.9190875 g 7108 grams of CaBr2 are needed
2.5 mol x 10-2
All you have to do is flip the numbers and reduce. If you have Ca+2 and Br-, Switch the numbers so you get CaBr2. 1 and 2 do not have any common factors so you don't have to reduce! CaBr2 is the final answer.
yes