0
What else can I help you with?
What is the reaction between silver nitrate and potassium iodide?
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
What is the equation when ammonia reacts with silver nitrate?
The equation for the reaction between ammonia and silver nitrate is: 2NH3 + AgNO3 → AgNH3 + NO3
Silver nitrate and potassium iodide?
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
What happens when iodide is mixed with silver nitrate?
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
What is the molecular equation of silver nitrate and potassium iodide?
AgNO3(aq) + KI(aq) = KNO3(aq) + AgI(s) This is a classic test for halogens, and AgI precipitates down as a yellow solid.
What is the reaction between silver nitrate and potassium iodide?
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
How can you distinguish between a precipitate of silver chloride and silver iodide?
Silver chloride appears white, while silver iodide appears yellow. You can further distinguish between the two by adding ammonia solution - silver chloride will dissolve in ammonia, forming a colorless solution, while silver iodide remains unaffected.
What is observed when a solution of potassium iodide is added to silver nitrate solution?
A yellow precipitate of silver iodide is formed due to the reaction between potassium iodide and silver nitrate, as silver iodide is insoluble. The reaction can be described by the equation: 2KI (aq) + AgNO3 (aq) → AgI (s) + 2KNO3 (aq)
Silver nitrate solution is reacted with sodium iodide solution?
This is a precipitation reaction. Halides of silver are insoluble in water (except silver fluoride) whereas all nitrates are soluble in water. Sodium salts are soluble. Thus, silver iodide is the precipitate. Formula: AgNO3(aq) + NaI(aq) -> AgI(s) + NaNO3(aq)
What is the formula for ammonium iodide silver nitrate?
Ammonium iodide is NH4I Silver nitrate is AgNO3
Write word equations to descrbe the reaction silver iodide and potassium acetate?
There is no reaction, because silver iodide is very insoluble.
What is the equation when ammonia reacts with silver nitrate?
The equation for the reaction between ammonia and silver nitrate is: 2NH3 + AgNO3 → AgNH3 + NO3
What happens when silver nitrate solution is added to potassium iodide solution?
A white precipitate of silver iodide forms due to the reaction between silver ions and iodide ions, leaving potassium nitrate in solution. This reaction is a double displacement reaction and is used as a test for iodide ions.
Silver nitrate and potassium iodide?
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
What is the evidence that a chemical reaction occured in silver nitrate and potassium iodide?
The evidence that a chemical reaction occurred in the reaction between silver nitrate and potassium iodide is the formation of a yellow precipitate of silver iodide. This precipitate forms due to the exchange of ions between the two reactants, resulting in the creation of a new compound with different chemical properties than the original substances.
Reaction of sodium iodide with silver nitrate?
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Two solutions mixed to make silver iodide?
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
