In a 0.25M solution of NaOH, the concentration of hydroxide ions (OH-) is also 0.25M. This is because NaOH dissociates completely in water to form Na+ and OH- ions. OH- represents the hydroxide ion in solution.
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
it is a base, because when NaOH is added to water, it gives off OH- ions.
The atomic weight of Na-OH is 23+16+1= 40. So to prepare the one N solution of Na-OH, you need to add 40 grams of Na-OH in one litre of water. To prepare the 4N Na-OH solution, you need to add 160 grams of Na-OH in one litre of water.
NaOH, sodium hydroxide is a strong base. This is because it dissociates completely in solution becoming a strong electrolyte. Na(+) and OH(-) ions in solution.
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
5.7
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
NaOH, sodium hydroxide is a strong base. This is because it dissociates completely in solution becoming a strong electrolyte. Na(+) and OH(-) ions in solution.
Bases, for example sodium hydroxide - NaOH.
Sodium hydroxide (NaOH) itself is a solid compound, but it can be dissolved in water to form a solution. When NaOH is dissolved, it dissociates into sodium ions (Na⁺) and hydroxide ions (OH⁻), creating a strongly alkaline solution. Thus, while NaOH is not a solution in its solid form, it becomes one when properly dissolved in water.
Aluminium hydroxide = Al(OH)3 , and Zinc hydroxide = Zn(OH)2 , is redissolved in excess Sodium hydroxide = NaOH (in water solution) : Al(OH)3 + NaOH + H2O ----> NaAl(OH)4 Zn(OH)2 + NaOH + H2O ----> Na2Zn(OH)4
Fe3+ + 3OH- _____> Fe(OH)3
it is a base, because when NaOH is added to water, it gives off OH- ions.
The atomic weight of Na-OH is 23+16+1= 40. So to prepare the one N solution of Na-OH, you need to add 40 grams of Na-OH in one litre of water. To prepare the 4N Na-OH solution, you need to add 160 grams of Na-OH in one litre of water.
NaOH, sodium hydroxide is a strong base. This is because it dissociates completely in solution becoming a strong electrolyte. Na(+) and OH(-) ions in solution.