The balanced equation is as follows:
KIO3 + AgNO3 --> KNO3 + AgIO3
Ag+ + NO3¯ + K+ + Cl¯ → AgCl + K+ + NO3¯
KCl + AgNO3 --> KNO3 + AgCl(s)
That simple with silver chloride precipitating out of solution.
KI + AGNO3 -> AgI + KNO3
AgNO3 + KBr = AgBr + KNO3
AgNO3 + KIO3 ----> AgIO3 +
KNO3+AgI
kbr + cl2
AgCl and KNO3.
AgNO3(aq) + KCl(aq) = AgCl(s) + KNO3(aq) This is the classic taste for halogens. In thisd case AgCl precipiates down as a white solid.
equivalent weight of silver nitrate = 169.87 so 0.1 N Ag NO3 = 16.987 gm /litre of AgNO3 now equivalent weight of KCl = 74.55 so 0.1 N KCl = 7.455 gm/litre so 0.1 N AgNO3 = 0.1N KCl = 7.456 gm of KCl [ not mg ]
The balanced equation is AgNO3 + NaCl --> AgCl + NaNO3. No coefficients are needed because everything bonds in a 1:1 molar ratio.
kbr + cl2
AgCl and KNO3.
AgNO3(aq) + KCl(aq) = AgCl(s) + KNO3(aq) This is the classic taste for halogens. In thisd case AgCl precipiates down as a white solid.
It forms AgCl + KNO3 or Silver chloride + potassium nitrate
the reaction is as follows-AgNO3 + KCl ----->AgCl +KNO3here the silver nitrate(AgNO3) reacts with potassium chloride(KCl) to form potassium nitrate(KNO3) and insoluble AgCl.
equivalent weight of silver nitrate = 169.87 so 0.1 N Ag NO3 = 16.987 gm /litre of AgNO3 now equivalent weight of KCl = 74.55 so 0.1 N KCl = 7.455 gm/litre so 0.1 N AgNO3 = 0.1N KCl = 7.456 gm of KCl [ not mg ]
KCl will not decompose
The balanced equation is AgNO3 + NaCl --> AgCl + NaNO3. No coefficients are needed because everything bonds in a 1:1 molar ratio.
Potassium chloride is react with AgNO3 , the chloride ion subtract from potassium chloride to form silver chloride precipitate and potassium nirate. KCl + AgNO3 → KNO3 + AgCl↓
BaCl2 + K2So4 ----> BaSo4 + 2 KCl
The balanced equation is Cl2 + 2 KBr -> Br2 + 2 KCl.
It is a "double replacement" reaction between silver nitrate and potassium chloride, to yield silver chloride and potassium nitrate.AgNO3+ KCl → AgCl + KNO3