The formations of these compounds from elements are as follows.
2 Na + S --> Na2S
2K + I2 --> 2KI
These two reagents do not react with each other.
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.
The balanced equation is 2KI + Cl2 -> 2KCl + I2. This is balanced by ensuring that there are the same number of each type of atom on both sides of the equation.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
There is no reaction, because all product ( if reaction goes) would be soluble. so : H+ + Cl- + K+ + I- = H+ + Cl- + K+ + I- and than all of them dare present as a ions only.
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
The balanced equation for KI + BaS is 2Kl + BaS -> BaI2 + K2S.
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.
The balanced equation is 2KI + Cl2 -> 2KCl + I2. This is balanced by ensuring that there are the same number of each type of atom on both sides of the equation.
The balanced equation for the formation of silver iodide is: 2 AgNO3 + 2 KI → 2 AgI + 2 KNO3
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
H2O2 + 2 KI --> 2 KOH + I2
There is no reaction, because all product ( if reaction goes) would be soluble. so : H+ + Cl- + K+ + I- = H+ + Cl- + K+ + I- and than all of them dare present as a ions only.
Nothing happens, all possible salts are very soluble: Potassium and sodium salts are always soluble!
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
KI would be potassium iodine, but you asked KL, and there is no L element.
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.