* Carbon = 79.9g, hydrogen = 20.1g (work out the mass of each element) * 79.9/12 = 6.66, 20.1/1 = 20.1 (divide mass by Atomic Mass number) * Ratio = 6.66 : 20.1 = 1:3 (simplify to find lowest ratio) * Therefore the simplest ratio and the empirical formula is CH3.
To determine the molecular formula from the empirical formula and the vapor density, we first need to calculate the empirical formula mass. The empirical formula mass of CH2O is 12g (carbon) + 2g (hydrogen) + 16g (oxygen) = 30g/mol. Next, we compare the vapor density with the empirical formula mass to find the factor by which the empirical formula mass is multiplied to get the molecular mass. The factor is 1.5 (45 / 30 = 1.5). Finally, we multiply the subscripts in the empirical formula by this factor to get the molecular formula, which is C3H6O3.
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.
To determine the molecular formula from the empirical formula and gram formula mass, first calculate the empirical formula mass of C4H9 (4 carbons + 9 hydrogens). Then, divide the gram formula mass by the empirical formula mass to find the ratio. Finally, multiply the subscripts in the empirical formula by this ratio to get the molecular formula, which in this case is C8H18.
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
The actual mass must be divided by the empirical mass. This was derived from the following equation: (subscript)(empirical formula) = (molecular formula) subscript = (molecular formula)/(empirical formula)
The molar mass of the hydrocarbon is 58 g/mol. To calculate the molar mass, we use the formula: molar mass = mass / moles. Since the hydrocarbon has 5 carbons, the molecular formula is C5H12 (for pentane).
This is a hydrocarbon called Acetylene (IUPAC name : Ethyne). It contains two carbon atoms joined with a triple bond, and 2 hydrogen atoms connected to the two carbon atoms with a single bond. Its structure : H-C≡C-H
To determine the molecular formula from the empirical formula and the vapor density, we first need to calculate the empirical formula mass. The empirical formula mass of CH2O is 12g (carbon) + 2g (hydrogen) + 16g (oxygen) = 30g/mol. Next, we compare the vapor density with the empirical formula mass to find the factor by which the empirical formula mass is multiplied to get the molecular mass. The factor is 1.5 (45 / 30 = 1.5). Finally, we multiply the subscripts in the empirical formula by this factor to get the molecular formula, which is C3H6O3.
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.
To find the molecular formula from the empirical formula (C2H5), we need to know the molecular mass of the compound. Since the formula implies a molecular mass of 29 g/mol (12 g/mol for carbon and 1 g/mol for hydrogen), if we divide the molecular mass of the compound by the empirical formula mass (C2H5 = 212 + 51 = 29 g/mol), we find that the molecular formula is the same as the empirical formula, C2H5.
To determine the molecular formula from the empirical formula and gram formula mass, first calculate the empirical formula mass of C4H9 (4 carbons + 9 hydrogens). Then, divide the gram formula mass by the empirical formula mass to find the ratio. Finally, multiply the subscripts in the empirical formula by this ratio to get the molecular formula, which in this case is C8H18.
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
The actual mass must be divided by the empirical mass. This was derived from the following equation: (subscript)(empirical formula) = (molecular formula) subscript = (molecular formula)/(empirical formula)
By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.