This reaction is:
CH3COOCH2CH3 + H2O ↔ CH3COOH + CH3CH2OH
The products are acetic acid and ethanol.
Balanced chemical equation: Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (g) Oxidation half-reaction: Zn (s) --> Zn2+ (aq) + 2e- Reduction half-reaction: 2H+ (aq) + 2e- --> H2 (g)
Assuming you know how to find the equivalence point on the titration curve, and assuming it is not [strong acid/strong base] or [weak acid/weak base], all you need to do is find the half equivalence point, which gives you the pKa of the first solution. Then to get the Ka, you go 10-pKa .
The half equation for the reduction of copper oxide by carbon is: CuO + C -> Cu + CO
Milk has a pH of 6(slightly more acidic than pure water). So I would guess half and half to be slightly more basic than milk.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
To form ethanol, the chemical equation shows that one mole of glucose is converted to two moles of ethanol. The molar mass of glucose is around 180 g/mol and that of ethanol is around 46 g/mol. Therefore, to produce 127g of ethanol, you would need 127g/(46g/mol) = 2.76 moles of ethanol. Since glucose to ethanol is a 1:2 ratio, you would need half as many moles of glucose, which would be 1.38 moles of glucose.
Balanced chemical equation: Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (g) Oxidation half-reaction: Zn (s) --> Zn2+ (aq) + 2e- Reduction half-reaction: 2H+ (aq) + 2e- --> H2 (g)
Assuming you know how to find the equivalence point on the titration curve, and assuming it is not [strong acid/strong base] or [weak acid/weak base], all you need to do is find the half equivalence point, which gives you the pKa of the first solution. Then to get the Ka, you go 10-pKa .
In the standard equation for an ellipse, b is half the length of the _____ axis.Answer:
At the half-equivalence point, the moles of acid initially present are equal to the moles of base added. This corresponds to half the acid being neutralized, forming a buffer solution. The pH can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base and [HA] is the concentration of the acid.
Preparation of Buffer Solution: A buffer solution is prepared by mixing equal amount of weak acid and its salt, such as, acetic acid (CH3COOH) and sodium acetate (CH3COONa) or weak base and its salt, such as, ammonia (NH3) and ammonium chloride (NH4Cl).
12 ounces of beer delivers approximately half an ounce of ethanol.
The half equation for the reduction of copper oxide by carbon is: CuO + C -> Cu + CO
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Not exactly sure what you mean about "aluminum's half life equation." Exponential decay, from where we get the half-life equation from, has nothing to do with mass, atomic number, etc... and therefore has nothing to do with any particular isotope.
This is the equation of a semi-circle, or a half circle.
I'll answer half of the question. Ethanol is the alcohol that is in alcoholic beverages -- liquor, beer, wine, etc. There are too many variables to answer the second part of the question. The amount of ethanol necessary to intoxicate depends on the concentration of the ethanol, the weight of the person, whether they are male or female, what they have eaten before imbibing, their tolerance to alcohol, etc.