The actual structure of the molecule is needed to answer this as there are more than one compounds with the formula asked in the question.
The hybridization state of each carbon atom in nemotin is sp3.
The carbon in CH3CHCH2 has sp3 hybridization. Each carbon atom forms four sigma bonds, leading to the tetrahedral geometry characteristic of sp3 hybridization.
The molecule C4H8 has sp3 hybridization. Each carbon atom forms four sigma bonds with one another, resulting in the formation of a tetrahedral shape around each carbon atom.
The hybridization of HCCl3 is sp3. Each carbon atom in the molecule is bonded to three chlorine atoms and one hydrogen atom, resulting in a tetrahedral geometry around each carbon atom, which corresponds to an sp3 hybridization.
There are 4 carbon atoms, which each individually act as a central atom since they are surrounded entirely by the hydrogen atoms. Each carbon forms 4 sigma bonds, therefore, each carbon atom has a hybridization state of sp^3.
The hybridization state of each carbon atom in nemotin is sp3.
The carbon in CH3CHCH2 has sp3 hybridization. Each carbon atom forms four sigma bonds, leading to the tetrahedral geometry characteristic of sp3 hybridization.
The molecule C4H8 has sp3 hybridization. Each carbon atom forms four sigma bonds with one another, resulting in the formation of a tetrahedral shape around each carbon atom.
The hybridization of HCCl3 is sp3. Each carbon atom in the molecule is bonded to three chlorine atoms and one hydrogen atom, resulting in a tetrahedral geometry around each carbon atom, which corresponds to an sp3 hybridization.
There are 4 carbon atoms, which each individually act as a central atom since they are surrounded entirely by the hydrogen atoms. Each carbon forms 4 sigma bonds, therefore, each carbon atom has a hybridization state of sp^3.
The hybridization of CH3 is sp3. Each carbon atom forms four sigma bonds with hydrogen atoms, resulting in a tetrahedral geometry and sp3 hybridization.
The hydrogens in propane are sp3 hybridized. Each hydrogen atom is bonded to a carbon atom, which forms four sigma bonds in a tetrahedral geometry, leading to sp3 hybridization for the hydrogens.
The hybridization of each central atom in the order from a to e is sp3, sp2, sp3d, sp3d2, and sp3d3.
The carbon atoms in C2H2 have sp hybridization. Each carbon atom forms two sigma bonds by overlapping one s orbital with one p orbital to create two sp hybrid orbitals. These orbitals then overlap with the sp hybrid orbitals of the other carbon atom to form two carbon-carbon sigma bonds.
In propenoic acid (also known as acrylic acid), the carbon-carbon double bond and the carbonyl group result in sp2 hybridization for both carbon atoms in the double bond and the carbonyl carbon. The oxygen atom in the carbonyl group has sp2 hybridization, while the remaining carbon atoms have sp3 hybridization.
You will need to supply a structural formula for this question to be answered. Or you could simply count the number of other atoms bonded to each carbon: 4 means it's sp3, 3 is sp2, and 2 is sp.
The hybridization of the bonding orbitals of carbon in carbon tetrachloride are sp3 hybridized. The hybridization occurs between the s orbital of the hydrogen atom and the px, py, pz orbitals of the carbon atom, hence it is sp3 hybridized.