0
What else can I help you with?
How many moles are in 92g of ethanol?
To find the number of moles in 92g of ethanol, we first need to know the molar mass of ethanol, which is approximately 46g/mol. Then, we divide the given mass by the molar mass to get the number of moles. So, 92g of ethanol is equal to 2 moles.
What is the mole fraction of ethanol C2H5OH in an aqueous soloution that is 50.0 ethanol by mass?
To find the mole fraction of ethanol (C2H5OH), you first need to calculate the moles of ethanol in the solution. Then, calculate the total moles of all components in the solution. Finally, divide the moles of ethanol by the total moles to get the mole fraction. In this case, since the solution is 50% ethanol by mass, you can assume 50 g of the solution to make calculations simpler.
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
What is the mole fraction of water in a water ethanol solution that is 57 percent water by mass?
To calculate the mole fraction of water in the solution, we first need to determine the moles of water and ethanol present. Given that the solution is 57% water by mass, we can assume the remaining 43% is ethanol. From there, we can convert the mass percentages to moles using the molar masses of water and ethanol, and finally, calculate the mole fraction of water by dividing the moles of water by the total moles of the solution.
How many moles are represented by 11.5g of c2H5oh?
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
What is the total sample size (in grams) for a sample of ethanol (CH3CH2OH) which contains 3.36 g of oxygen?
9.675 g Since oxygen has an average atomic weight of 15.999 g/mol that would make it 0.21 moles of oxygen. Ethanol has one atom of oxygen per molecule so that means 0.21 moles of ethanol. Since ethanol has a molecular weight of 46.07 g/mole, 0.21 moles of ethanol would have a mass of 9.675 g.
How many moles are in 92g of ethanol?
To find the number of moles in 92g of ethanol, we first need to know the molar mass of ethanol, which is approximately 46g/mol. Then, we divide the given mass by the molar mass to get the number of moles. So, 92g of ethanol is equal to 2 moles.
How many moles are represented by 16.0 g of ethanol C2H5OH?
To find the number of moles of ethanol (C2H5OH) in 16.0 g, first calculate its molar mass. The molar mass of C2H5OH is approximately 46.07 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we have moles = 16.0 g / 46.07 g/mol, which equals approximately 0.347 moles of ethanol.
What is the mole fraction of ethanol C2H5OH in an aqueous soloution that is 50.0 ethanol by mass?
To find the mole fraction of ethanol (C2H5OH), you first need to calculate the moles of ethanol in the solution. Then, calculate the total moles of all components in the solution. Finally, divide the moles of ethanol by the total moles to get the mole fraction. In this case, since the solution is 50% ethanol by mass, you can assume 50 g of the solution to make calculations simpler.
What is the number of moles in 508 g of ethanol?
To find the number of moles in 508g of ethanol (C2H5OH), first calculate the molar mass of ethanol: 2(12.01) + 6(1.01) + 1(16.00) = 46.08 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 508g / 46.08 g/mol ≈ 11 moles.
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
What is the mole fraction of water in a water ethanol solution that is 57 percent water by mass?
To calculate the mole fraction of water in the solution, we first need to determine the moles of water and ethanol present. Given that the solution is 57% water by mass, we can assume the remaining 43% is ethanol. From there, we can convert the mass percentages to moles using the molar masses of water and ethanol, and finally, calculate the mole fraction of water by dividing the moles of water by the total moles of the solution.
How many moles of ethanol are contained in 57.38 grams of ethanol C2H5OH?
remember that mass divided by molecular mass = the number of moles the atomic mass' are as follows : C = 112.01 O = 16 H = 1.01 the molecular mass of a methanol molecule is that of 2 carbons 6 hydrogens and one oxygen = 46.08g following you divide 25g(measure of mass) by 46.08(atomic mass) = 10.54 mole. (the grams will cancel with each other leaving mole as the unit if you want to take a strictly mathmathical point of view)
How many moles are represented by 11.5g of c2H5oh?
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
How many moles of glucose are required to form 127g of ethanol?
To form ethanol, the chemical equation shows that one mole of glucose is converted to two moles of ethanol. The molar mass of glucose is around 180 g/mol and that of ethanol is around 46 g/mol. Therefore, to produce 127g of ethanol, you would need 127g/(46g/mol) = 2.76 moles of ethanol. Since glucose to ethanol is a 1:2 ratio, you would need half as many moles of glucose, which would be 1.38 moles of glucose.
How many moles of ethanol per liter?
AnswerThe density of ethanol is 0.789 g/cm³ , and there are 1000 cm3 in a liter, so 1 liter weighs 0.789 kilograms.Density = mass/volume, So mass=density*volume.So, weight of 1L ethanol = 0.789*1 => 0.789KG
How much energy is released when 1.56 kg of ethanol 46.0 g mol freezes The heat of fusion of ethanol is 4.94 kJ mol?
To calculate the energy released when 1.56 kg of ethanol freezes, first convert the mass of ethanol to moles using its molar mass. Then, use the heat of fusion of ethanol to determine the energy released using the formula: Energy released = moles of ethanol x heat of fusion.
