Ca-40 Br-80 O-16 40+[(80*2)+(16*6)]*2=296g per mol
The molar mass of Ca(BrO3)2 (calcium bromate) is 343.898 g/mol.
To calculate the mass of Ca(OH)2 required to have 10g of calcium, first determine the molar mass of Ca(OH)2 (74.1 g/mol). Since calcium accounts for 40% of the mass in Ca(OH)2, the mass of Ca in 10g Ca is 4g. Using the molar ratio (Ca:Ca(OH)2) to find the mass of Ca(OH)2 required, the answer is 60g.
To find the mass of 24 moles of Ca(OH)2, you first need to calculate the molar mass of Ca(OH)2. This involves adding the atomic masses of calcium (Ca), oxygen (O), and hydrogen (H) in the compound. Once you have the molar mass, you can then multiply it by the number of moles (24 moles) to get the mass.
The chemical formula for the compound formed between barium and bromine is BaBr2. In this compound, barium forms a +2 cation (Ba^2+) and bromine forms a -1 anion (Br^-), resulting in the formula BaBr2.
The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.
The molar mass of Ca(BrO3)2 (calcium bromate) is 343.898 g/mol.
295.88 g/mol
No, this statement is incorrect. The molar mass of CaCO3 (calcium carbonate) is 100.09 g/mol, while the molar mass of Ca(NO3)2 (calcium nitrate) is 164.08 g/mol. Therefore, the molar mass of Ca(NO3)2 is greater than that of CaCO3.
The molar mass of calcium acetate is approximately 142 g/mol.
To calculate the mass of Ca(OH)2 required to have 10g of calcium, first determine the molar mass of Ca(OH)2 (74.1 g/mol). Since calcium accounts for 40% of the mass in Ca(OH)2, the mass of Ca in 10g Ca is 4g. Using the molar ratio (Ca:Ca(OH)2) to find the mass of Ca(OH)2 required, the answer is 60g.
1.15 (g CaCO3) / 100.1 (g/mol CaCO3) =1.149*10-2 (mol Ca)1.149*10-2 (mol Ca) = 1.149*10-2 (mol Ca) * 40.08 (g/mol Ca) = 0.4604 g Ca0.4604 g Ca = 0.4604 g Ca / 2.70 g Supplement = 0.1705 * 100% = 17.1% Calcium (m%)
To find the number of moles in 16.4 g of calcium nitrate, Ca(NO3)2, you first need to calculate its molar mass. The molar mass of Ca(NO3)2 is approximately 164.1 g/mol. Using the formula for moles (moles = mass / molar mass), you can calculate the moles: ( \text{moles} = \frac{16.4 , \text{g}}{164.1 , \text{g/mol}} \approx 0.100 , \text{moles} ). Therefore, there are about 0.100 moles of Ca(NO3)2 in 16.4 g.
CaCl2 = MM(Ca) + 2*MM(Cl) = 40 + 35.5 * 2 =111
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To find the mass of 24 moles of Ca(OH)2, you first need to calculate the molar mass of Ca(OH)2. This involves adding the atomic masses of calcium (Ca), oxygen (O), and hydrogen (H) in the compound. Once you have the molar mass, you can then multiply it by the number of moles (24 moles) to get the mass.
The chemical formula for the compound formed between barium and bromine is BaBr2. In this compound, barium forms a +2 cation (Ba^2+) and bromine forms a -1 anion (Br^-), resulting in the formula BaBr2.
The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.