Mg(OH)2 = 24.31 + (16.00 + 1.008)x2 = 24.31 + (17.008)x2 = 24.31 + 34.016) = 58.326 = 58.33 g/mol
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
The molar mass of magnesium thiotellurite (Mg2TeS2O6) is calculated by adding up the atomic masses of magnesium (Mg), tellurium (Te), sulfur (S), and oxygen (O) in the compound. The molar mass is approximately 485.86 g/mol.
The formula for magnesium cyanide is Mg(CN)2. To find the molar mass, you would add the molar mass of one magnesium atom (24.305 g/mol), and two cyanide ions (26.02 g/mol each). Therefore, the molar mass of magnesium cyanide is 76.345 g/mol.
The molar mass of magnesium can be determined using gas law stoichiometry when the mass of magnesium reacted and the volume of gas produced are known. By measuring the volume of gas produced during the reaction of magnesium with an acid, and knowing the pressure, temperature, and number of moles of gas, the molar mass of magnesium can be calculated using the ideal gas law equation PV = nRT and stoichiometry relationships.
The molar mass of Mg O = 40.3044 g/mol
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
To completely precipitate 86.9mg of magnesium from seawater, you would need to add an equal molar amount of sodium hydroxide. The molar mass of magnesium is about 24.3 g/mol, so 86.9mg is equivalent to about 3.57 mmol of magnesium. You would need the same amount of mmol of sodium hydroxide to completely precipitate the magnesium.
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
not sure exactly, but it has magnesium, oxygen and iodine
the molar mass of potasium hydroxide is 56 g/mole
The molar mass of magnesium thiotellurite (Mg2TeS2O6) is calculated by adding up the atomic masses of magnesium (Mg), tellurium (Te), sulfur (S), and oxygen (O) in the compound. The molar mass is approximately 485.86 g/mol.
get the volume of the chemical and the mass and divide the mass by it's volume
Molar mass of magnesium is 24gmol-1. mass of 1.5 mg mole 36g.
To find the mass of 24.6 formula units of magnesium oxide, we first need to determine the molar mass of magnesium oxide. Magnesium has a molar mass of approximately 24.3 g/mol, and oxygen has a molar mass of approximately 16.0 g/mol. Therefore, the molar mass of magnesium oxide (MgO) is 24.3 + 16.0 = 40.3 g/mol. Next, we multiply the molar mass of MgO by the number of formula units (24.6) to find the total mass: 40.3 g/mol x 24.6 = 992.38 grams. Therefore, the mass of 24.6 formula units of magnesium oxide is approximately 992.38 grams.
The formula for magnesium cyanide is Mg(CN)2. To find the molar mass, you would add the molar mass of one magnesium atom (24.305 g/mol), and two cyanide ions (26.02 g/mol each). Therefore, the molar mass of magnesium cyanide is 76.345 g/mol.
The molar mass of magnesium can be determined using gas law stoichiometry when the mass of magnesium reacted and the volume of gas produced are known. By measuring the volume of gas produced during the reaction of magnesium with an acid, and knowing the pressure, temperature, and number of moles of gas, the molar mass of magnesium can be calculated using the ideal gas law equation PV = nRT and stoichiometry relationships.
The molar mass of Mg O = 40.3044 g/mol