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Q: What is the molarity of a solution containing 325 g of NaCl dissolved in 750.ml of solution?

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You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.

Moles of glucose = 80g/180g/mol = 0.444 moleMolarity = 0.444/0.75L = 0.5926 M

Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.

3.75 mol

.188 mols

Related questions

You have 2.5 moles in 750ml. However molar means per 1000ml. Therefore 2.5/750*1000 gives you your answer. The answer is 3.333 molar.

1.99 M

Molarity is mols of solute over liters of solution. 85.0g NaNO3 (1mol/85g ) = 1mol 750ml = 0.75 Liters so, 1/0.75 = 1.3 Molar

Well potassium nitrate has a molecular weight of 101. If there are 346g in 750ml there will be 346 x 1000/750 = 461.334 g in 1 liter. The solution is thus 461.334/101 = 4.57 molar (2 decimal places).

You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.

Moles of glucose = 80g/180g/mol = 0.444 moleMolarity = 0.444/0.75L = 0.5926 M

Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M

Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.

3.75 mol

750ml

750ml = 75cl

.188 mols

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