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What is the molarity of a solution that has 6 moles of NaOH in 3 kg of water?
Molarity = moles of solute/Liters of solutionThat 3 kg of water would present a problem, but water = 1 gram/ml in density, so....3 kg = 3000 grams1g/ml H2O = 3000 grams H2O/X ml= 3000 ml = 3 Litersso,Molarity = 6 moles Na/3 Liters= 2 M NaOH-----------------
What is molarity of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
To find the molarity, we first need to convert the mass of water to volume using the density of water. Given the density of water is approximately 1000 g/L, 6 kg of water is equivalent to 6000 g or 6 L. Next, calculate the molarity using the formula Molarity (M) = moles of solute / liters of solution. In this case, 2 moles of NaOH in 6 L of water gives a molarity of 0.33 M.
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
What is the molarity of a solution made by dissolving 2 moles of Na OH in 6 kg of water?
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
Dissolve 2 moles of NaOH in 6 kg of water?
To dissolve 2 moles of NaOH in 6 kg of water, you would need to calculate the molarity of the NaOH solution. First, you would find the molar mass of NaOH (40 g/mol) and then divide the moles by the mass of water in kg to find the molarity. This would be approximately 0.33 mol/L.
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
What is the molarlity of a colution made by dissolving 6 moles of NaOH in 3 kg of water?
To find the molarity, we first need to convert the mass of water to moles. Since 1 kg of water is approximately 1000 moles, 3 kg of water is 3000 moles. Then, molarity is calculated by dividing the number of moles of solute (NaOH) by the volume of solution in liters. So, the molarity would be 6 moles / 3 L = 2 M.
What is the molarity of a solution that has 6 moles of NaOH in 3 kg of water?
Molarity = moles of solute/Liters of solutionThat 3 kg of water would present a problem, but water = 1 gram/ml in density, so....3 kg = 3000 grams1g/ml H2O = 3000 grams H2O/X ml= 3000 ml = 3 Litersso,Molarity = 6 moles Na/3 Liters= 2 M NaOH-----------------
What is the molarity of a solution that has 6 moles CaCl2 in 3 kg of water?
To find the molarity of the solution, first, we need to determine the total volume of the solution in liters. Since the density of water is approximately 1 kg/L, 3 kg of water corresponds to about 3 liters. Molarity (M) is calculated as moles of solute divided by the volume of solution in liters. Thus, the molarity of the solution is ( \frac{6 \text{ moles}}{3 \text{ L}} = 2 \text{ M} ).
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
What is molarity of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
To find the molarity, we first need to convert the mass of water to volume using the density of water. Given the density of water is approximately 1000 g/L, 6 kg of water is equivalent to 6000 g or 6 L. Next, calculate the molarity using the formula Molarity (M) = moles of solute / liters of solution. In this case, 2 moles of NaOH in 6 L of water gives a molarity of 0.33 M.
What is the molarity of a solution made by dissolving 2 moles of Na OH in 6 kg of water?
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
What is the molatity of a solution made by dissolving 6 moles of NaOH in 3 kg of water?
Molarity is defined as the number of moles of solute per liter of solution. To find the molarity of the NaOH solution, we first need to determine the total volume of the solution. Since the density of water is approximately 1 kg/L, 3 kg of water is roughly 3 L. Therefore, the molarity of the solution is 6 moles of NaOH divided by 3 L of solution, which equals 2 M (moles per liter).
Dissolve 2 moles of NaOH in 6 kg of water?
To dissolve 2 moles of NaOH in 6 kg of water, you would need to calculate the molarity of the NaOH solution. First, you would find the molar mass of NaOH (40 g/mol) and then divide the moles by the mass of water in kg to find the molarity. This would be approximately 0.33 mol/L.
What is the molarity of a solution that dissolves 6 moles of NAOH in 3 kg of solution?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution in liters. In this case, we need to convert the 3 kg of solution to liters first. Given that the density of water is approximately 1 kg/L, 3 kg of solution is equivalent to 3 L. Therefore, the molarity would be 2 M (6 moles NAOH/3 L of solution).
What would you need to do to calculate the molarity of 0.2kg of nail in3kg of water?
To calculate the molarity of the nail in water, you first need to determine the number of moles of the substance in the nail. This requires knowing the chemical composition of the nail to find its molar mass. Once you have the number of moles, you can use the formula for molarity (M = moles of solute/volume of solution in liters) by converting the mass of water to liters, assuming the density of water is approximately 1 kg/L. Finally, divide the moles of the nail by the volume of water in liters to find the molarity.
How many moles of solute particles are in a solution with 0.50 moles of glucose and 2.0 kg water?
The solution is 0,25 M.
