C14 H 28 has 14 carbon atoms and 28 hydrogen atoms it is not an alkane though it is an alkene because the formula for alkanes is Cn H2n+2 whereas alkenes have the formula Cn H2n so if you apply the 14 carbon atoms to the first part of the equation so C14 then the amount of hydrogen atoms has to be two times that amount and what is 14 times 2? 28! So it must be an alkene!
There is not one particular name but six possible isomer of C4H8 with different names:
This formula may have several isomers the names of four common isomers are, 1-butyne, 2-butyne, 1,2-butadiene, 1,3-butadiene.
Empirical formula (lowest whole number) for C4H8 is CH2, obtained by dividing by 4.
If the C4H8 compound is butene-1 or -2 or 2-methylpropene, the product is one of the chlorobutanes with general formula C4H9Cl. If the C4H8 compound is cyclobutane, there is no reaction at standard temperature and pressure.
C4H8 may be an alkene, Butene or methyl propene and may be a cycloalkane, cyclobutane or methyl cyclopropane.
Cycloalkene is represented by a molecular formula. This formula is CnH (2n - 2) wherein C and H are the compositions of the cyclic and 2H is removed from the end C to connect to the other C.
The alkene will have 8 hydrogen atoms. It's chemical formula would be C4H8.
Carbon tetrachloride is the chemical name for the molecular formula CCl4. In contrast C4H8 refers to the family of butene molecules.
Empirical formula (lowest whole number) for C4H8 is CH2, obtained by dividing by 4.
If the C4H8 compound is butene-1 or -2 or 2-methylpropene, the product is one of the chlorobutanes with general formula C4H9Cl. If the C4H8 compound is cyclobutane, there is no reaction at standard temperature and pressure.
C4H8 may be an alkene, Butene or methyl propene and may be a cycloalkane, cyclobutane or methyl cyclopropane.
When it burns completely, each molecule of C4H8 becomes 4 molecules of CO2 and 4 molecules of H2O.
trigonal planar
Well its actually called cyclobutane. Erm, it's actually called butene - with an e
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
Cycloalkene is represented by a molecular formula. This formula is CnH (2n - 2) wherein C and H are the compositions of the cyclic and 2H is removed from the end C to connect to the other C.
C2h4, c3h6, c4h8
the answers is 6 _apex