First off, NaCO3 is unbalanced. It should be Na2CO3.
Na2CO3 --> 2 Na+ + CO32-
CuSO4 --> Cu2+ + SO42-
Together only Cu2+ and CO32- react with each other, Sodium and Sulfate don't form a precipitate and are called: tribune ions, ie. don't react and can be left out of the reaction equation (marked by hooked parenthesis [.+.] )
Cu2+ + [SO42-+ 2 Na+] + CO32- --> (CuCO3)precip. solid+ [SO42-+ 2 Na+]
Simpler:
Cu2+aq. + CO32-aq. --> (CuCO3)precip. solid
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The net ionic equation for the reaction between HCHO2 (formic acid) and KOH (potassium hydroxide) is HCHO2 + OH- --> HCO2- + H2O. This equation shows the formation of formate ion and water from the reaction of formic acid with hydroxide ion in potassium hydroxide.
The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
CuSO4 + 2 KOH = Cu(OH)2 + K2SO4Copper hydroxide is insoluble in water.
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
The net ionic equation for the reaction between HCHO2 (formic acid) and KOH (potassium hydroxide) is HCHO2 + OH- --> HCO2- + H2O. This equation shows the formation of formate ion and water from the reaction of formic acid with hydroxide ion in potassium hydroxide.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
HNO3 + KOH ----> KNO3 + H2O This is the complete equation this is the net ionic equation. Because it is a strong acid (HNO3) and a strong base (KOH) it will always be H+ + OH- -------> H2O
The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.
The eqnet ionic equation is HCN + OH- --> H2O + CN-
Balanced :2 K + 2 H2O ----> 2 KOH + H2
Plus 1 charge