First work out the moles
So do 36g / 80 (80 is bromine's relative Atomic Mass number)
You have 0.45 M
Then, do 0.45 * 6.02*10^23
You get 2.7*10^23, which is your answer
The average mass of two atoms of beryllium is approximately 8.00 atomic mass units (amu).
To find the number of grams in 0.02 moles of beryllium iodide (BeI2), you would first calculate the molar mass of BeI2, which is 262.83 g/mol. Then, you would multiply the molar mass by the number of moles: 0.02 moles * 262.83 g/mol = 5.26 grams of beryllium iodide.
There are 4.8 x 10^24 hydrogen atoms in 360 grams of water. This is calculated by using Avogadro's number to convert the mass of water to moles, and then using the chemical formula of water (H2O) to determine the number of hydrogen atoms present in 1 mole of water.
To find the number of atoms in 175 g of calcium, we need to first calculate the number of moles of calcium using its atomic mass (40.08 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to get the total number of atoms in 175 g of calcium.
To find the mass of He containing the same number of atoms as 5.0 g Kr, we need to use the fact that atoms are indivisible entities. First, determine the number of atoms in 5.0 g Kr using the molar mass of Kr. Then, calculate the mass of He containing the same number of atoms by dividing the atomic mass of He by Avogadro's number and scaling it up to match the number of Kr atoms.
The average mass of two atoms of beryllium is approximately 8.00 atomic mass units (amu).
The formula is: number of moles = g Be/9,012.
BeCl2 One atom of beryllium and two atoms of chloride. = 79.912 grams/mole
To find the number of grams in 0.02 moles of beryllium iodide (BeI2), you would first calculate the molar mass of BeI2, which is 262.83 g/mol. Then, you would multiply the molar mass by the number of moles: 0.02 moles * 262.83 g/mol = 5.26 grams of beryllium iodide.
1 mole of the element has 6.023 x 1023 atoms 1 mole = 4 g of helium = 7 g of lithium = 9 g of beryllium = 11 g of boron = 12 g of carbon = 14 g of nitrogen = 16 g of oxygen
The atomic mass is the same as the atomic weight therefore it is 9.01218. Beryllium is a non metal element. Atomic mass of it is 9.01. The atomic mass number, which is distinct from the atomic mass and the atomic weight, is 9.
The density of beryllium is 1,85 g/cm3.
There are 4.8 x 10^24 hydrogen atoms in 360 grams of water. This is calculated by using Avogadro's number to convert the mass of water to moles, and then using the chemical formula of water (H2O) to determine the number of hydrogen atoms present in 1 mole of water.
To find the number of atoms in 175 g of calcium, we need to first calculate the number of moles of calcium using its atomic mass (40.08 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to get the total number of atoms in 175 g of calcium.
Beryllium density: 1,848 g/cm3 Bismuth density: 9,78 g/cm3
The number of atoms of lead is 6,68.10e23.
To find the mass of He containing the same number of atoms as 5.0 g Kr, we need to use the fact that atoms are indivisible entities. First, determine the number of atoms in 5.0 g Kr using the molar mass of Kr. Then, calculate the mass of He containing the same number of atoms by dividing the atomic mass of He by Avogadro's number and scaling it up to match the number of Kr atoms.